Answer Now!! Which expression can be used to find the area, in square cm, of this parallelogram?

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

A, because parallelogram is the same as a rectangle, just tilted a bit. therefore the method is just base X height.

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Simply by using rationalize denominators.<br><br> 2a^-1/2

Advocard [28]

Pemdas, so exponent before multiply
so do a^-1/2 then multiply it by 2

remember that $x^ \frac{m}{n}= \sqrt[n]{x^m}$ and
$x^{-m}= \frac{1}{x^m}$
therefor, $a^ \frac{-1}{2}= \frac{1}{a^ \frac{1}{2} } = \frac{1}{ \sqrt{a} }$
the we multiply by 2

$\frac{2}{ \sqrt{a} }$

8 0

3 years ago

The difference of a number m and 18 how would you write a algebraic expression

Tpy6a [65]

Answer:

m - 18

Step-by-step explanation:

Symbolically, that difference would be written as m - 18.

6 0

3 years ago

the ratio of the areas of two rectangles is 4 to 5. if the area of the larger rectangle is 135 square feet, what is the area of

-BARSIC- [3]

Divide the number 135 and 5. It is going to be 27. Then you multiply 27 times 4. Then you get your answer which is 108.
Proportion set up....
small 4 ? small
----- --------
big 5 135 big
Cross multiply 4x135= 540
and then divide 540/5= 108

8 0

3 years ago

Sara made 8 necklaces. She used 9 beads on each necklace. The beads came in bags of 6 each. How many bags

motikmotik

Answer:

12 bags

Step-by-step explanation:

9×8=72 beads all together

72/6=12 bags of beads

4 0

2 years ago

Please answer my question .q bo 4 d and e

sdas [7]

4 (e)
sin^8 x - cos^8 x
= (sin^4 x + cos^4 x)(sin^4 x - cos^4 x)
= (sin^4 x + cos^4 x)(sin^2 x - cos^2x)(sin^2 x +cos^2 x)
= (sin^4x + cos^4 x)( sin^2 x- cos^2 x)

Sorry I cant do 4 (d).

5 0

3 years ago