I don’t know what you’re tying to say
Fairly straightforward question. She works 30 days and is late 80% or 0.8
We can model our equation
Num days late = late percentage * num working days
Basically fine portion of working days that she was late.
Num days late = 0.8 * 30=24
So Deborah was late 24 out of 30 working days. Would appreciate a brainliest
Answer:
The larger number is -6, the smaller number is -15
Step-by-step explanation:
We have two numbers, a and b.
We know that one number is larger than another by 9.
Then we can write:
a = b + 9
then a is larger than b by 9 units.
If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:
(a + 10) + 3*b = -41
So we got two equations:
a = b + 9
(a + 10) + 3*b = -41
This is a system of equations.
One way to solve this is first isolate one variable in one of the two equations:
But we can see that the variable "a" is already isolated in the first equation, so we have:
a = b + 9
now we can replace that in the other equation:
(a + 10) + 3*b = -41
(b + 9) + 10 + 3*b = -41
now we can solve this for b.
9 + b + 10 + 3b = -41
(9 + 10) + (3b + b) = -41
19 + 4b = -41
4b = -41 -19 = -60
b = -60/4 = -15
b = -15
then:
a = b + 9
a = -15 + 9 = -6
a = -6
Answer:
x=a+b
Step-by-step explanation:
Just move a to the other side (by adding it)
Answer:
7) (f+g)(x) = 4^x +5x -5
8) (f-g)(x) = 4^x +x +5
Step-by-step explanation:
7) add the two expressions.
(f+g)(x) = f(x) +g(x) = (4^x +3x) +(2x -5)
(f+g)(x) = 4^x +5x -5
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8) subtract g(x) from f(x).
(f-g)(x) = f(x) -g(x) = (4^x +3x) -(2x -5) = 4^x +3x -2x +5
(f-g)(x) = 4^x +x +5
