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vitfil [10]
3 years ago
5

Tom and 29 friends (30 total) are to sit in three rows of 10 at a movie theatre. They madea rule that Within each row, they must

sit in order of tallest to shortest with the tallestperson on the left. Given that there are no two people with the same height and there areno restrictions on where a person must sit, how many different seating arrangements arepossible
Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

The answer is "6000".

Step-by-step explanation:

It seems to be a total of 30 buddies there. Every column has 10 seats so that the 10 pals are now in a row. Of all the other 20 buddies, 10 are on the following row. And we have ten friends remaining and that they are sitting in the next row.

Therefore the possibility of sitting is:

30 \times 20 \times 10 = 6000

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