Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that .
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer:
D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60
Step-by-step explanation:
The formula for the perimeter of a rectangle is .
If the width is and the length is , then the perimeter becomes:
.
.
.
Therefore the answer is
D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60
Subtract (10 divided into fifths) from (20 divided into half)
= (20 divided into half) - (10 divided into fifths)
= (20 / 2) - (10 / 5)
If you need to solve this expression expression:
= 10 - 2
= 8
I hope this helps you
It looks like you are trying to compute the improper integral,
or some flavor of this. If this interpretation is correct, substitute <em>u</em> = ln(<em>x</em>) and d<em>u</em> = d<em>x</em>/<em>x</em>. Then