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makvit [3.9K]
3 years ago
5

Water flows from the bottom of a storage tank at a rate of r(t) = 200 − 4t liters per minute, where 0 ≤ t ≤ 50. find the amount

of water that flows from the tank during the first 35 minutes.

Mathematics
2 answers:
Aleks [24]3 years ago
5 0
The answer for your problem is shown on the picture.

user100 [1]3 years ago
3 0

Answer:

The amount of water that flows from the tank during the first 35 minutes is 4550 liters.

Step-by-step explanation:

We know that the rate is given by r(t)=200-4t and the problem asks for the net change (<em>the amount of water</em>) for the first 35 minutes.

We can use the Net change theorem:

The integral of a rate of change is the net change:

\int\limits^b_a {F'(x)} \, dx =F(b)-F(a)

Applying the above theorem we get

\int\limits^{35}_0 {200-4t} \, dt

\int _0^{35}200dt-\int _0^{35}4tdt\\\\\left[200t\right]^{35}_0-\left[\frac{t^2}{2}\right]^{35}_0\\\\7000-2450\\\\4550

The amount of water that flows from the tank during the first 35 minutes is 4550 liters.

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Answer:

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Step-by-step explanation:

First, you have to calculate the volume of cone and cylinder seperately by applying the formulas :

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3 years ago
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4 years ago
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vaieri [72.5K]

Answer:

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(b) Total No. of Proper Subsets = 127

Step-by-step explanation:

First we need to define the set of days of the week.

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(a)

The total no. of subsets of a given set is given by the following formula:

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Answer:

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Step-by-step explanation:

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