For this case we have the following equation:
f (x) = x ^ 2 + bx-49
Deriving we have:
f '(x) = 2x + b
We match zero:
0 = 2x + b
We clear x:
x = -b / 2
The axis of symmetry is at x = 8, therefore:
x = -b / 2 = 8
Clearing b:
b = -2 * (8)
b = -16
Answer:
the value of b is:
b = -16
Step-by-step answer:
Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals
Ra = 2Fcos(a) ..............................(1)
Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals
Rb = 2Fcos(b)..............................(2)
We are given that
Ra = 2Rb ....................................(3)
Substitute (1) & (2) in (3) gives
2Fcos(a) = 2(2Fcos(b))
Expand
2Fcos(a) = 4Fcos(b)
Simplify
cos(a) = 2 cos(b) QED
Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.
Have a nice day!
Answer:
B
Step-by-step explanation:
f(x) = x²+49 , rewrite the equation
x² +7² =0 , to find the roots make f(x) =0 and subtract 7² from both sides
x² = -7², square root both sides
√x² =√-7², consider √-1 =i
x= ±7i
the roots are -7i and 7i
Some how Katrina has forgotten to write a check amount down in here check book. to find out the amount you would subtract 190.62 from 172.62
Ten to the second power or ten squared is 100. 247 divided by 100 is 2.47