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zhenek [66]
3 years ago
15

Please help Ik taking the map staar

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

I think it's d

Step-by-step explanation: Because they have equal sides and length

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Can you please help me give the Complete solution <br><br>(nonsence report )​
Tasya [4]

\huge \boxed{\mathfrak{Question} \downarrow}

  • Factorise the polynomials.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

__________________

<h3><u>1. x² + 4x + 4</u></h3>

{x}^{2}  + 4x + 4

Factor the expression by grouping. First, the expression needs to be rewritten as x²+ax+bx+4. To find a and b, set up a system to be solved.

a+b=4  \\ ab=1\times 4=4

As ab is positive, a and b have the same sign. As a+b is positive, a and b are both positive. List all such integer pairs that give product 4.

1,4  \\ 2,2

Calculate the sum for each pair.

1+4=5  \\ 2+2=4

The solution is the pair that gives sum 4.

a=2 \\  b=2

Rewrite x² + 4x + 4 as (x² + 2x) + (2x + 4)

\left(x^{2}+2x\right)+\left(2x+4\right)

Take out the common factors.

x\left(x+2\right)+2\left(x+2\right)

Factor out common term x+2 by using distributive property.

\left(x+2\right)\left(x+2\right)

Rewrite as a binomial square.

b. \:  \:  \boxed{ \boxed{{(x + 2)}^{2} }}

__________________

<h3><u>2. x² - 8x + 16</u></h3>

x ^ { 2 } - 8 x + 16

Factor the expression by grouping. First, the expression needs to be rewritten as x²+ax+bx+16. To find a and b, set up a system to be solved.

a+b=-8  \\ ab=1\times 16=16

As ab is positive, a and b have the same sign. As a+b is negative, a and b are both negative. List all such integer pairs that give product 16.

-1,-16  \\ -2,-8  \\ -4,-4

Calculate the sum for each pair.

-1-16=-17  \\ -2-8=-10  \\ -4-4=-8

The solution is the pair that gives sum -8.

a=-4  \\ b=-4

Rewrite x²-8x+16 as \left(x^{2}-4x\right)+\left(-4x+16\right).

\left(x^{2}-4x\right)+\left(-4x+16\right)

Take out the common factors.

x\left(x-4\right)-4\left(x-4\right)

Factor out common term x-4 by using distributive property.

\left(x-4\right)\left(x-4\right)

Rewrite as a binomial square.

d. \:  \:  \boxed{\boxed{\left(x-4\right)^{2} }}

__________________

<h3><u>3. 4x² + 12xy + 9y²</u></h3>

4 x ^ { 2 } + 12 x y + 9 y ^ { 2 }

Use the perfect square formula, a^{2}+2ab+b^{2}=\left(a+b\right)^{2}, where a=2x and b=3y.

e. \:  \: \boxed{ \boxed{\left(2x+3y\right)^{2} }}

__________________

<h3><u>4. x⁴ - 2x² + 1</u></h3>

x ^ { 4 } - 2 x ^ { 2 } + 1

To factor the expression, solve the equation where it equals to 0.

x^{4}-2x^{2}+1=0

By Rational Root Theorem, all rational roots of a polynomial are in the form p/q, where p divides the constant term 1 and q divides the leading coefficient 1. List all candidates p/q.

± \: 1

Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.

x=1

By Factor theorem, x-k is a factor of the polynomial for each root k. Divide x⁴-2x²+1 by x-1 to get x³+x²-x-1. To factor the result, solve the equation where it equals to 0.

x^{3}+x^{2}-x-1=0

By Rational Root Theorem, all rational roots of a polynomial are in the form p/q, where p divides the constant term -1 and q divides the leading coefficient 1. List all candidates p/q.

± \:  \: 1

Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.

x=1

By Factor theorem, x-k is a factor of the polynomial for each root k. Divide x³+x²-x-1 by x-1 to get x²+2x+1. To factor the result, solve the equation where it equals to 0.

x^{2}+2x+1=0

All equations of the form ax²+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 2 for b and 1 for c in the quadratic formula.

x=\frac{-2±\sqrt{2^{2}-4\times 1\times 1}}{2}  \\

Do the calculations.

x=\frac{-2±0}{2}  \\

Solutions are the same.

x=-1

Rewrite the factored expression using the obtained roots.

\left(x-1\right)^{2}\left(x+1\right)^{2}  \\  = a. \:  \:  \boxed{ \boxed{\left(x^{2}-1\right)^{2}}}

__________________

  • <em>Refer to the attached picture too.</em>

7 0
3 years ago
Which two expressions are equivalent to 5^2/5^8<br> A 1/5^6<br> B 1^-6<br> C (5^2)^-3<br> D (5^2)^-8
Sauron [17]

Answer:

Carbon (C), nonmetallic chemical element in Group 14 (IVa) of the periodic table. Although widely distributed in nature, carbon is not particularly plentiful—it makes up only about 0.025 percent of Earth's crust—yet it forms more compounds than all the other elements combined.

6 0
3 years ago
Read 2 more answers
WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
Rufina [12.5K]

Answer:

(2, -1)

Step-by-step explanation:

because that's where the lines intersect

8 0
3 years ago
Read 2 more answers
Tell whether the angles are complementary or supplementary. Then fir<br> the value of x.
Helga [31]

Answer:

Step-by-step explanation:

4. 10x + 30 = 90

    10x = 60

     x = 6

   complementary

5. 4x + 40 + 3x = 180

   7x + 40 = 180

   7x = 140

    x = 20

   supplementary

4 0
2 years ago
Hoy can You record decimal notation for decimals and fractions
Lisa [10]
Example:
9.075= 9+ 0/10 + 7 + 100+ 5/1000

=9000/1000 + 0/1000 + 70/1000 + 5/1000

=9075/1000
5 0
3 years ago
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