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3 years ago

Please help Ik taking the map staar

Mathematics

1 answer:

krok68 [10]3 years ago

4 0

Answer:

I think it's d

Step-by-step explanation: Because they have equal sides and length

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If f(x)=x2+2x+3 what is the value of f(x) when x=6

Marat540 [252]

The answer is 51

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7 0

4 years ago

I NEED HELPPPP PLEASE

denpristay [2]

Plug them in then solve from left to light

3 0

4 years ago

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Points (4, 3) and (0, 6) Mid point

V125BC [204]

Answer:

(3.5,3)

Step-by-step explanation:

Midpoint= (x¹+x²/2, y¹+y²/2)

x¹=4

x²=3

y¹=0

y²=6

Put your values into the formula

(4+3/2,0+6/2)

(7/2, 6/2)

(3.5,3)

5 0

3 years ago

Is (3,5) a solution of y>x-3?

Advocard [28]

Answer:

no it's not

Step-by-step explanation:

4 0

3 years ago

A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi

viktelen [127]

Answer:

Side length = $\sqrt{\frac{A}{3} }$ cm , Height = $\frac{1}{2} \sqrt{\frac{A}{3} }$ cm , Volume = $\frac{A\sqrt{A}}{6\sqrt{3} }$ cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

$y = \frac{A - x^{2} }{4x}$

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( $\frac{A - x^{2} }{4x}$ )

V = $\frac{Ax - x^{3} }{4}$

To find max volume put V' = 0

So taking derivative equation becomes

$\frac{A - 3 x^{2} }{4} = 0$

A = 3 $x^{2}$

$x^{2}$ = $\frac{A}{3}$

x = $\sqrt{\frac{A}{3\\} }$

put value of x in equation 1

y = $\frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }$

y = $\frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }$

y = $\frac{1}{2} \sqrt{\frac{A}{3} }$

So the volume will be

V = $x^{2}$ × y

Put values of x and y from equation 2 & 3

V = $\frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )$

V = $\frac{A\sqrt{A}}{6\sqrt{3} }$

8 0

4 years ago