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fredd [130]
3 years ago
15

Ben walks 25 miles from home to work. If he walks the first 5 miles in 1 hour, the second 5 miles in 1.4 hours, the third 5 mile

s in 1.7 hours and the last 5 miles in 1.8 hours, how long will it take him to complete the 25 mile walking distance? (Enter numeric value only. If rounding is required, round to the nearest tenth).
Mathematics
1 answer:
natka813 [3]3 years ago
8 0

<u>Answer:</u>

The total time taken to complete 25 miles is 7.6 hours.

Solution:

Ben walks 5 miles in 1 hour,

Second 5 miles in 1.4 hours,

Third 5 miles in 1.7 hours,

Last 5 miles in 1.8 hours

So he walked total 20 miles in (1+1.4+1.7+1.8) hours = 5.9 hours = 6 hours (approximately)

So his average speed is \left(\frac{20}{6}\right) miles/hours = 3.33 miles/hours.  

i.e. he travels 3.3 miles in 1 hour,

Then, he travels 1 miles in \left(\frac{1}{3.3}\right) hours

Hence the total time he will take to walk 25 miles is \left(25 \times\left(\frac{1}{3.3}\right)\right) \text { hours }\Rightarrow \left(\frac{25}{3.3}\right) \text { hours } = 7.5757 hours

That is approximately 7.57 or 7.6 hours.

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Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

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Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

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Step-by-step explanation:This question Sets Up two equations with 2 unknowns        

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