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sesenic [268]
3 years ago
7

angle a and angle b are complementary angles. angle a measures 67 degrees. what is the measure of angle b?

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0
The answer is 23 because they have to add up to 90 :) - beanz
hi2738
3 years ago
yes that is correct, and on a thing called khan academy, it is the opposite.
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Profit, P(x), is the difference between revenue, R(x), and cost, C(x), so P(x) = R(x) - C(x). Which expression represents P(x),
harkovskaia [24]

Answer:

x^4-3x^3+x^2-4

Step-by-step explanation:

Given the following functions

R(x) = 2x^4 – 3x^3 + 2x – 1 and

C(x) = x^4 – x^2 + 2x + 3

We are to find the profit function P(x)

P(x) = R(x) - C(x)

P(x) = 2x^4 – 3x^3 + 2x – 1 - ( x^4 – x^2 + 2x + 3)

P(x) = 2x^4 – 3x^3 + 2x – 1 - x^4 + x^2 - 2x - 3

Collect the like terms

P(x) = 2x^4-x^4-3x^3+x^2+2x-2x-1-3

P(x) = x^4-3x^3+x^2+0-4

P(x) = x^4-3x^3+x^2-4

Hence the required profit function P(x) is x^4-3x^3+x^2-4

5 0
3 years ago
Read 2 more answers
Write the number in different ways
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4. 15 tens, 1 hundred, 5 tens
150
5. 18 tens, 1 hundred, 8 tens
180


note: I hope this helps. I haven't done this in a long time. Sorry X(
3 0
3 years ago
The seventh-grade class is building target areas for a PE activity. The bases for the game will be circular in shape. The diamet
murzikaleks [220]
19.6 would be the area of a single base circle πr² is the area formula
5 0
3 years ago
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I've been struggling a bit with Composite Figures. This is 2 ones I've really struggled with though so, could I have some help?
Natali5045456 [20]
You are right with : Which shapes could a pentagon be decomposed into to find its area? Chose all that apply.
C. five triangles
D. one triangle and one trapezoid
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6 0
3 years ago
A,B and C are the vertices of one triangle.
dsp73

Answer:


Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

Proof: If we prove the basic proportionality theorem that is \frac{AD}{DB}=\frac{AE}{EC}, then it proves that DE is parallel to BC.

Now, Mid Point D has coordinates=(\frac{4+2}{2},\frac{6-2}{2})=(3,2) and Mid Point E has coordinates=(\frac{4-2}{2},\frac{6-4}{2})=(1,1)

Now, AD= \sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}

DB=\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}

AE=\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}

EC=\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}

Now, \frac{AD}{DB}=\frac{AE}{EC}

=\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}

Hence, \frac{AD}{DB}=\frac{AE}{EC}

Thus, By basic proportionality theorem, DE is parallel to BC.

4 0
3 years ago
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