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Alona [7]
3 years ago
8

Which graph represents a function? Please help me

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0
Think the 3 graph would be a function the graph the the arrow going straight up.
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Solve using the zero product property x^2+11x+30=0 can you help please
skelet666 [1.2K]
I think it's x=-5, -6
4 0
3 years ago
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

6 0
3 years ago
Please help me out! As soon as possible.
Liula [17]

Answer:

Number of hours gardening

Step-by-step explanation:

12g

g = Number of hours gardening

6 0
2 years ago
0.5 0.45 0.405 4.5 least to greatest
babymother [125]
0.405, 0.45 , 0.5 , 4.5 : Least to greatest!
5 0
3 years ago
8.5(4+3h)-h simplified
nikklg [1K]

Answer:

34+24.5h

Step-by-step explanation:

8.5(4+3h)-h\\\\=8.5(4)+8.5(3h)-h\\\\=34+25.5h-h\\\\=34+24.5h

4 0
3 years ago
Read 2 more answers
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