All categories

3 years ago

Help please! Lines a and b are parallel. What is the measure of angle m?

Mathematics

1 answer:

AlexFokin [52]3 years ago

8 0

So the transversal (line that crosses lines a and b) is 180 since its a straight line. given the angle degree 125, you can do 180-125 to get angle m.

You might be interested in

When solving a system of inequalities, which of the following methods are used? A.guess and check

yarga [219]

Answer:

Option B - graphing is the correct answer.

Step-by-step explanation:

To solve a system of inequalities we need graphing. Inequality tells us about the relative size of two values. When we graph the x and y co-ordinates, the solution is not the drawn line, but the area of the coordinate plane that satisfies the inequality. In inequalities, multiple solutions can be possible.

Plug and chug method does not a complete solution, it only tells where a point belongs. Guess and check does not apply here.

7 0

3 years ago

An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object

Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

$1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2 + \frac{1}{2} at^2\\3) v = v_0 + at$

What do we already know?

$v_0 = 29.4 ms^-1$
The launch is straight up
$a = -9.81 ms^-2$ this is the gravitational acceleration $g$

$s_0 = 0 m$ , since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, $v = 0 ms^-2$

$v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m$

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

$s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2$

this is the equation of the whole trajectory that object makes.

and if you solve this by making $s = 0$ , you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0

3 years ago

HELPPP I WILL BRAINLIST!!

charle [14.2K]

Answer:

Step-by-step explanation:

8 (x -3) +7 = 2x (4 -17)

8(x -3) +7 = 2x (-13) here was the error because the had 13 that is incorrect

8x -24 +7 = -26x

8x -17 = -26x

-17 = -26x -8x

-17 = -34x

-17/-34 = x

1/2 =x

3 0

3 years ago

45 tens is the same as

MakcuM [25]

Tens refers to the unit 10,
This means that 45 10s is equal to:
45*10 = 450

Hope this helps! :)

8 0

3 years ago

Read 2 more answers

Transformation rules, HELP PLEASE, WILL GIVE BRAINLEIST

Tatiana [17]

1. (x , y) → (kx , ky) = Dilation ; similar image
2. (x , y) → (y , -x) = Rotation 90 counterclockwise ; congruent
3. (x , y) → (-x , y) = Reflection over y-axis ; congruent
4. (x , y) → (-x , -y) = Rotation 180 ; congruent
5. (x , y) → (x, -y) = Reflection over x-axis ; congruent
6. (x , y) → (-y , x) = Rotation 90 clockwise ; congruent
7. (x , y) → (x + a , y + b) = Translation ; congruent

Hope this helps :)

8 0

3 years ago