Assuming your solving for y:
py+7=6y+q
-6y -7 -6y -7
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
Answer:
<em>p ≥ 5</em>
<em>Scott will buy at least 5 kilograms of candy.</em>
Step-by-step explanation:
<u>Inequalities</u>
The candy Scott buys cost $7 per kilogram.
Let's set p=number of kilograms of candy Scott will buy.
The money spent to buy p kilograms of candy is 7p dollars.
The condition states he will spend at least $35 on candies, thus the following inequality is formed:
7p ≥ 35
Dividing by 7:
p ≥ 35/7
Operating:
p ≥ 5
Scott will buy at least 5 kilograms of candy.
Answer:It
It can be 12, 13, 14 and more up
Step-by-step explanation:
Is that because 12+7= 19 which is bigger than 18
Answer:
20,442,240 account numbers are possible.
Step-by-step explanation:
The first character has 10 possible values.
The next 2 has 26 * 26 = 676 possible combinations.
The last 4 has 9*8*7*6 = 3024 possible combinations.
So the answer is 10 * 676 * 3024
= 20,442,240.
Given:
3:15 pm - start of first showing.
30 minutes break;
20 minutes late - 2nd showing.
4:50 - start of second showing.
4:50 - 0:20 = 4:30 should be the start of the second showing.
4:00 - 4:30 = 1/2 hour break
3:15 - 4:00 = duration of the 1st showing. 45 minutes in all.
4:50 + 0:45 = 5:35 pm end of the 2nd showing.
Yes, the 2nd showing will be over by 6:30 pm.
