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Ksju [112]
2 years ago
11

8,25,42,, Sequence find the 82nd term

Mathematics
1 answer:
Citrus2011 [14]2 years ago
7 0

Answer:

1385

Step-by-step explanation:

1) the difference is d=25-8=42-25=17;

the sequence given in the condition is arithmetic one (linear relationship).

2) in order to calculate the value of the 82d term:

a(n)=a(1)+d*(n-1), where n - number of required term (it is 82), then

a(82)=8+17*(82-1)=8+1377=1385.

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f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}

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