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3 years ago

-5/8 ÷ 9/10 A. -25/36 B. -9/16 C. -45/80 D. -1/36

Mathematics

2 answers:

Oduvanchick [21]3 years ago

5 0

A. -25/36

If There Is Any Other Fraction problems That You Need Help With, Go To This Site http://www.calculatorsoup.com/calculators/math/fractions.php

saul85 [17]3 years ago

4 0

A. -25/36

- 5/8 <span>÷ 9/10 = - 5/8 x 10/9 = - 5/4 x 5/9 = -25/36</span>

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Write a problem to fit this equation 2K + 5 =29

Degger [83]

2K + 5 = 29

(2 x K) + 5 = 29

29 - 5 = 24

24 divided by 2 = 12 (This is K)

K = 12

(2 x 12) + 5 = 29

24 + 5 = 29

6 0

3 years ago

Plz help thanks! Arusha draws a rectangular prism that is made up of two connector cubes each with edge length e. The surface Ar

Stolb23 [73]

Answer:

Step-by-step explanation:

The SA would be 10e² because there are 10 squares.

The V would be 2e³ because there are 2 cubes.

Part A

If e = 5 cm, simply plug it into the SA formula we have already.

SA = 10e² = 10*5² = 10*25 = 250 cm².

Part B

If e = 5cm, simply plug it into the V formula we have already.

V = 2e³ = 2*5³ = 2*125 = 250 cm³.

Now we need to find what percent of 250 is 150?

250p = 150

p = 150/250 = 3/5 = 0.6 = 60%

4 0

3 years ago

Help me please thank youuuuu ^_^

OverLord2011 [107]

Answer:

x = 6

Step-by-step explanation:

2x - 3 = 9

so 9+3 = 12, and 12÷2 = 6

the value of x is 6

5 0

2 years ago

You are given the following information obtained from a random sample of 5 observations. 20 18 17 22 18 At 90% confidence, you w

Margaret [11]

Answer:

The null hypothesis is

$H_o : \mu = 21$

The Alternative hypothesis is

$H_a : \mu< 21$

$\sigma_{\= x} = 0.8944$

$t = -2.236$

Yes the mean population is significantly less than 21.

Step-by-step explanation:

From the question we are given

a set of data

20 18 17 22 18

The confidence level is 90%

The sample size is n = 5

Generally the mean of the sample is mathematically evaluated as

$\= x = \frac{20 + 18 + 17 + 22 + 18}{5}$

$\= x = 19$

The standard deviation is evaluated as

$\sigma = \sqrt{ \frac{\sum (x_i - \= x)^2}{n} }$

$\sigma = \sqrt{ \frac{ ( 20- 19 )^2 + ( 18- 19 )^2 +( 17- 19 )^2 +( 22- 19 )^2 +( 18- 19 )^2 }{5} }$

$\sigma = 2$

Now the confidence level is given as 90 % hence the level of significance can be evaluated as

$\alpha = 100 - 90$

$\alpha = 10$ %

$\alpha =0.10$

Now the null hypothesis is

$H_o : \mu = 21$

the Alternative hypothesis is

$H_a : \mu< 21$

The standard error of mean is mathematically evaluated as

$\sigma_{\= x} = \frac{\sigma}{ \sqrt{n} }$

substituting values

$\sigma_{\= x} = \frac{2}{ \sqrt{5 } }$

$\sigma_{\= x} = 0.8944$

The test statistic is evaluated as

$t = \frac{\= x - \mu }{ \frac{\sigma }{\sqrt{n} } }$

substituting values

$t = \frac{ 19 - 21 }{ 0.8944 }$

$t = -2.236$

The critical value of the level of significance is obtained from the critical value table for z values as

$z_{0.10} = 1.28$

Looking at the obtained value we see that $z_{0.10}$ is greater than the test statistics value so the null hypothesis is rejected

6 0

3 years ago

4. Which set is an example of like fractions?

Andrew [12]

A, they both equal to 1 when simplified

6 0

3 years ago

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