How many time that 6688 could into 16 which is 418
<u>Answer:</u>
plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE
answer = CI = 3108 RUPEES
<u>Step-by-step explanation:</u>
i am doing the method in which u find the simple interest of first year then second year.
SI FOR 1ST YEAR= P X R X T / 100
SI = 2700 X 20 X 2 / 3 X 100 ( RATE OF INTEREST IS 20 / 3)
SI = 108000/300
SI = 360
SI FOR SECOND YEAR =
P = 2700 + 360= 3060
SI = 3060 X 20 X 2 / 300
SI= 122400 / 300
SI = 408
COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR
CI = 2700 + 408
CI = 3108 RUPEES
or u can solve be the method
CI = amount - principle
Amount= principle x (change in ratio) raised to time
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9 is your answer, hope this helps
<h3>
Answer:</h3>
square units (approximately 2338.26859)
<h3>
Step-by-step explanation:</h3>
The formula for finding the area of a regular hexagon when you know its side length is , where is the area and is the side length.
- Substitute in the side length.
- Simplify the exponent.
- Multiply.
- Divide.
is as simple as the solution can get without estimating, but you can estimate with a calculator to find that it is approximately 2338.26859.
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair =
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51