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Triss [41]
3 years ago
14

The river falls vertically compared to how far it flows horizontally. Find the

Mathematics
1 answer:
katovenus [111]3 years ago
7 0

Answer:

23 / 126

Step-by-step explanation:

46/252 = 23/126

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Andru [333]
Refer to the attached photo to see the problem worked out
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Tim walked 2/5 of a mile on Monday, 6/7 of a mile on Tuesday, and 2/3 of a mile on Wednesday. How far did he walk in all?
Nady [450]
2/5 + 6/7 + 2/3....lowest common denominator is 105

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What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

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3 years ago
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paraell

Step-by-step explanation:

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steposvetlana [31]

Answer:

Center = ( 1,-2)

radius = 2

6 0
3 years ago
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