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3 years ago

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An above ground swimming pool is leaking after 1 and 1/2 hours the pool has leaked 7/8 of a gallon of water how many gallons of

water per hour is the swimming pool leaking

1 answer:

Aleksandr [31]3 years ago

8 0

Answer:

In 1 hour the amount of water leaking from pool = $\frac{7}{12}$ gallon of water

Step-by-step explanation:

Given as :

The amount of Leaking of water from the pool = $\frac{7}{8}$ gallon

The time taken fro leaking $\frac{7}{8}$ gallon of water = 1 $\frac{1}{2}$ gallon hour

Or The time taken fro leaking $\frac{7}{8}$ gallon of water = $\frac{3}{2}$ hour

∵ $\frac{3}{2}$ hour takes for leaking $\frac{7}{8}$ gallon of water

∴ In 1 hour the amount of water leaking from pool = $\frac{7}{8}\setminus \frac{3}{2}$

Or, In 1 hour the amount of water leaking from pool = $\frac{7}{12}$ gallon of water Answer

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The Skittles jar has a radius of 3.5 cm and a height of 11.5 cm. Using the two given boxes for reference what would be a good es

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Answer:

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Step-by-step explanation:

The two given boxes for reference are presented below.

Since we know the dimensions of the first container, we can calculate its volume.

$V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3$

The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.

$v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3$

The second container held 258 skittles.

The volume of the second box is:

$V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3$

Using this facts, the volume of a single skittle would be

$v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3$

Therefore, the volume of single skittle is around to 0.42 cm³.

A skittle jar is a cylinder. Its volume is calculated by the formula

$V = r^2h \pi$ ,

where $r$ is the radius and $h$ is the height. From the given data, we have $r = 3.15 \text{cm}$ and $h = 11.5 \text{cm}$ . Hence, the volume of the jar is

$V = 3.5^2 \cdot 11.5 \cdot 3.14 = 442 \text{cm}^3$

Now, we can determine the number of skittles in the jar. Let $n$ be the number of skittles in the jar. Then,

$n = \frac{\text{volume of the jar}}{\text{volume of a skittle}} = \frac{V}{v} = \frac{442}{0.42} = 1052.38 \approx 1052\\$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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exis [7]

Answer:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

The resistance of a strain gauge is normally distributed with a mean of 100 ohms and a standard deviation of 0.3 ohms. To meet t

zloy xaker [14]

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Step-by-step explanation:

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For x = 99.3

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By using the standard normal distribution table, The proportion of gauges is acceptable is given by:-

$P(99.3$

Hence, the proportion of gauges is acceptable=0.6827

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3 years ago