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OLga [1]
3 years ago
9

Find the missing side of the right triangle and simplify your answer. X 8 16

Mathematics
1 answer:
Lisa [10]3 years ago
6 0

Answer:

please forgive me I just want points for my exam

Step-by-step explanation:

please forgive me I just want points for my exam

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37. Bowling Alley A charges $5 admission and $3.50 per game. Bowling Alley B
sdas [7]

a. The cost for A = 19, and B = 25.

b. The cost for A = 22.25, and B = 25

c. When you want to play more than five games.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

a. How much does it cost to play four games at each bowling alley?

a. 5 + 3.50 × 4 = 19, B is always $25

b. How much does it cost to play five games at each bowling alley?

b. 5 + 3.50 × 5 = 22.25, B is always $25

c. When is it financially more beneficial to bowl at Bowling Alley B?

c. 5 + 3.50 × 6 = 26, six games cost more than $25.

We can see from the solution that for any number of times we will be charged $25 but for less than 5 times the charges of B will be higher than the charges of A.

Therefore a.The cost for A = 19, and B = 25.The cost for A = 22.25, and B = 25 When you want to play more than five games.

To know more about expression follow

brainly.com/question/723406

#SPJ1

5 0
2 years ago
What is the measure of &lt;DCF
Shtirlitz [24]
129 degrees you just add DCE and ECF together
5 0
3 years ago
Read 2 more answers
Cakes and More baked 1,450 chocolate chip cookies. The bakery sold them in boxes of 25 cookies each. How much money will the bak
Rina8888 [55]

Answer:

$406

Step-by-step explanation:

Step one:

given data

Cakes and More baked 1,450 chocolate chip cookies

The bakery sold them in boxes of 25 cookies each

The number of boxes will be

1450/25

=58  boxes

Step two:

The cost per box is $7

hence the cost of 58 boxes will be

=7*58

=$406

4 0
3 years ago
Solve with completing the square method:<br>6x²-7x+2=0 and  ax²+bx+c=0
Norma-Jean [14]
6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^{2}-4ac = (-7)^{2}-4*6*2=49-48=1 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{7-\sqrt{1}}{2*6}=\frac{7-1}{12} =\frac{6}{12}= \frac{1}{ 2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{7+\sqrt{1}}{2*6}=\frac{7+1}{12} =\frac{8}{12}= \frac{2}{ 3}


7 0
4 years ago
A) 2-x,when x=5
MrRissso [65]

Answer:

a) 2-5 = -3

b) 3(4) + 2(4) = 20

c) (3(5)+2)(5-4) = 17

Step-by-step explanation:

Substitute the variables for their values and then solve from there. Hopefully this helps, I don't know if I answered your question fully.

7 0
3 years ago
Read 2 more answers
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