Ask question

Ask question

All categories

3 years ago

6

jennifers piggy bank contains nickles, dimes, and quarters. she has 4 more dimes then quarters and 3 times as many nickles as di

mes. the total value of the couns is $5.00. how many of each kind of coin does she have?

1 answer:

Liula [17]3 years ago

8 0

Jennifer have 8 quarters, 12 dimes and 36 nickels.

Step-by-step explanation:

Given,

Worth of coins = $5.00 = 5*100 = 500 cents

One quarter = 25 cents

One dime = 10 cents

One nickel = 5 cents

Let,

x = number of quarters

y = number of dimes

z = number of nickels

According to given statement;

25x+10y+5z=500 Eqn 1

y = x+4 Eqn 2

z = 3y

z = 3(x+4) => z = 3x+12 Eqn 3

Putting value of y and z from Eqn 2 and 3 in Eqn 1

$25x+10(x+4)+5(3x+12)=500\\25x+10x+40+15x+60=500\\50x+100=500\\50x=500-100\\50x=400$

Dividing both sides by 50

$\frac{50x}{50}=\frac{400}{50}\\x=8$

Putting x = 8 in Eqn 2

$y=8+4\\y=12$

Putting x=8 in Eqn 3

$z=3(8)+12\\z=24+12\\z=36$

Jennifer have 8 quarters, 12 dimes and 36 nickels.

Keywords: linear equation, substitution method

Learn more about substitution method at:

#LearnwithBrainly

You might be interested in

Segment FG begins at point F(-2, 4) and ends at point G(-2, -3). The segment is translated 3 units left and 2 units up, then ref

Alexus [3.1K]

Answer:

$F'G' = 7$

Step-by-step explanation:

Given

$F = (-2,4)$

$G = (-2,-3)$

Required

Distance of F'G'

The transformation that give rise to F'G' from FG are:

Translation
Reflection

The above transformations are referred to as rigid transformation, and as such the side lengths remain unchanged.

i.e.

$F'G' = FG$

Calculating FG, we have:

$FG = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

Where:

$F = (-2,4)$ --- $(x_1,y_1)$

$G = (-2,-3)$ --- $(x_2,y_2)$

$FG = \sqrt{(-2 - -2)^2 + (4 - -3)^2}$

$FG = \sqrt{(0)^2 + (7)^2}$

$FG = \sqrt{0 + 49}$

$FG = \sqrt{49}$

Take positive square root

$FG = 7$

Recall that:

$F'G' = FG$

$F'G' = 7$

6 0

3 years ago

Lucas invested money in two accounts: one paying 3% interest and the other paying 5% interest. He invested $100 more in the 5% a

Anni [7]

He invested "a" at 3% and "b" at 5%

now, he invested 100 more in "b", so, whatever "a" may be, b = a + 100

now, how much is the interest yield of each? well
how much is 3% of a? well, (3/100) * a, or 0.03a
and 5% of b? well (5/100) * b, or 0.05b

now, we know the total yield was 53 bucks, thus 0.03a + 0.05b = 53

thus $\bf \begin{cases}
\boxed{b}=a+100\\
0.03a+0.05b=53\\
----------\\
0.03a+0.05\left( \boxed{a+100} \right)=53
\end{cases}$

solve for "a", to see how much was invested at 3%

what about "b"? well, b = a + 100

3 0

3 years ago

ASAP <br>What is the domain?

WARRIOR [948]

real numbers hope it helps

7 0

3 years ago

Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

3 years ago

(a) Laura owns 6 shares of a certain stock. Yesterday the total value of her shares went down by

Kay [80]

$24/6=$4 Answers: Laura’s stock lost Four dollars per share in value.

8 0

2 years ago

Read 2 more answers