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3 years ago

Two spheres have volumes of 8,cm and 647 cmIf the surface area of the smaller sphere is 16 cm?, what is the surface

Mathematics

1 answer:

Olegator [25]3 years ago

7 0

Answer:

361.7cm²

Step-by-step explanation:

Volume of sphere 1= 8cm³

Volume of sphere 2 = 647cm³

But volume of sphere = 4/3πr³

The radius of sphere 2

647 = 4/3πr³

((3*647)/4)/π= r³

5.36544 = r

Surface area = 4πr²

Surface area for the big sphere

= 4π5.36544²

= 361.7cm²

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2=5 ; 3=9 ; 4=48 ; 5=220 ; 6=1,350<br> THEN 8 = ?

loris [4]

2=5 ;

3=9 ; 3*5 - 3*2

4=48 ; 4*9 + 4*3

5=220 ; 5*48 - 5*4

6=1,350 6*220 + 6*5

7= 9408 7*1350 - 7*6

THEN 8 = 8*9408 + 8*7 = 75320

7 0

3 years ago

Use pi=3<br> Calculate the area of a circle with a diameter of 10cm

GalinKa [24]

Area of a circle is 75 cm².

Area of a circle is computed by multiplying pi to the square of the radius.

A = πr²

diameter = 10 cm
radius = d/2 = 10/2 = 5 cm
pi = 3

A = 3(5cm²)
A = 3(25cm²)
A = 75 cm²

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3 years ago

Through (7,2); parallel to 3x-y=8.

Dovator [93]

Answer:

x=4 y=4

Step-by-step explanation:

4 0

3 years ago

Given that cos (x) = 1/3, find sin (90 - x)

ddd [48]

Answer:

$\sin(90^{\circ} - x)=\frac{1}{3}$

Step-by-step explanation:

Given: $\cos (x)=\frac{1}{3}$

We have to find the value of $\sin(90^{\circ} - x)$

Since Given $\cos (x)=\frac{1}{3}$

Using trigonometric identity,

$\sin(90^{\circ} - \theta)=\cos\theta$

Thus, for $\sin(90^{\circ} - x)$ comparing , we have,

$\theta=x$

We get,

$\sin(90^{\circ} - x)=\cos x=\frac{1}{3}$

Thus, $\sin(90^{\circ} - x)=\frac{1}{3}$

3 0

4 years ago

Read 2 more answers

Find the volume of each prism

o-na [289]

Volume of a prism=LWH
V=12 3/8 * 10*5
V=12.375 * 50
V=618.75
The volume of the prism is 618.75yd³

4 0

4 years ago