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spayn [35]
3 years ago
9

Two spheres have volumes of 8,cm and 647 cmIf the surface area of the smaller sphere is 16 cm?, what is the surface

Mathematics
1 answer:
Olegator [25]3 years ago
7 0

Answer:

361.7cm²

Step-by-step explanation:

Volume of sphere 1= 8cm³

=

Volume of sphere 2 = 647cm³

But volume of sphere = 4/3πr³

The radius of sphere 2

647 = 4/3πr³

((3*647)/4)/π= r³

5.36544 = r

Surface area = 4πr²

Surface area for the big sphere

= 4π5.36544²

= 361.7cm²

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Answer:

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Step-by-step explanation:

It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:

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  = cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)

  = sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))

  = (sin(x) +cos(x))·(sin(4x) +cos(4x))

Each of the sums in this product is of the same form, so each can be simplified using the identity ...

  sin(x) +cos(x) = √2·sin(x +π/4)

Then the given equation can be rewritten as ...

  cos(3x) +sin(5x) = 0

  2·sin(x +π/4)·sin(4x +π/4) = 0

Of course sin(x) = 0 for x = n·π, so these factors are zero when ...

  sin(x +π/4) = 0   ⇒   x = nπ -π/4

  sin(4x +π/4) = 0   ⇒   x = (nπ -π/4)/4 = (4nπ -π)/16

The solutions are ...

  x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n

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In Rhombus ABCD if BD is 24 ft and AD is 15 ft, then what is the length of AC?
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Answer:

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Step by Step Explanation.

Given.

Rhombus.

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AD = 15ft

Required

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