What is the completely factored form of this polynomial? X^4+12x^2+32

Mathematics

1 answer:

Varvara68 [4.7K]3 years ago

4 0

Answer:

Answer is "B"

$( {x}^{2} + 4)( {x}^{2} + 8)$

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Please help me ASAP!!!

Mama L [17]

9/20

A percentage is the same as showing a number over 100 and if we multiply 20 by 5 we get 100. So if we multiply 9 by 5 we get 45, giving us 45/100 which can be shown as 45%.

As a decimal, well if we say 100% equals 1.0, then 45% equals 0.45

7 0

3 years ago

Calculus help ASAP!!!

anastassius [24]

Let $c\in(0,\infty)$ . Then the definite integral can be split up at $t=c$ so that

$\displaystyle F(x)=\int_{t=2x}^{t=5x}\frac{\mathrm dt}t$
$\displaystyle=\int_{t=2x}^{t=c}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t$
$\displaystyle=-\int_{t=c}^{t=2x}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t$

Now take the derivative. By the fundamental theorem of calculus, you have

$\displaystyle\frac{\mathrm dF}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\left[\int_{t=c}^{t=5x}\frac{\mathrm dt}t-\int_{t=c}^{t=2x}\frac{\mathrm dt}t\right]$
$=\displaystyle\frac1{5x}\dfrac{\mathrm d}{\mathrm dx}[5x]-\frac1{2x}\dfrac{\mathrm d}{\mathrm dx}[2x]$
$=\dfrac5{5x}-\dfrac2{2x}$
$=\dfrac1x-\dfrac1x$
$=0$

Then integrating with respect to $x$ , we recover $F(x)$ and find that

$\displaystyle\int\dfrac{\mathrm dF}{\mathrm dx}\,\mathrm dx=\int0\,\mathrm dx$
$F(x)=C$

where $C$ is an arbitrary constant.