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morpeh [17]
3 years ago
8

WILL MARK BRAINLY IF CORRECT!

Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

15

Step-by-step explanation:

The given equation is

12( -  \frac{1}{6}x  -  \frac{2}{3}y =  - 5)

5( \frac{2}{5} x +  \frac{1}{5} y =  - 9)

When we multiply we obtain the equations:

- 2x  -  8y =  - 60

2x + y =  - 45

We add both equations to obtain:

- 7y =  - 105

Divide both sides by -7 to get:

y =  \frac{105}{7}  = 15

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the difference of two number is 28 if the larger number is three time of the smaller find the number​
Elza [17]

Set up an equation:

3x - x = 28

Simplify:

2x = 28

Divide both sides by 2

X = 14

3(14) = 42

The numbers are 42 and 14

5 0
3 years ago
A boxer is put on a diet to gain 20 lb in four weeks. The boxer gains 4 1/3 lb the first week and 5 5/6 lb the second week. How
V125BC [204]

Answer:

9.8 lbs

Step-by-step explanation:

4 1/3 + 5 5/6= 10 1/6

20 - 10 1/6 = 9.8

7 0
3 years ago
The fish population in a local lake is 10,000. The population increase by half every year. Which function represents the fish po
sweet-ann [11.9K]

Answer:

5. f(x) = 10,000 (1.5)^x

Step-by-step explanation:

We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.

Let's test it.

Initial:

10,000

After 1 year

10,000 + (.5*10000)

10,000 + 5000 = 15,000

After 2 years

15,000 + (.5*15000)

15,000 + 7500 = 22,500

Let's try our equation.

f(x) = 10,000 (1.5)^x

x = 2

10,000(1.5)^2

10,000(2.25) = 22,500

The same!

7 0
3 years ago
Read 2 more answers
Practice analyzing quantitative relationships.
ANEK [815]

Answer:

Sorry can't see on school computer :(

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council
fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = \frac{x-1100}{200}

P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517

4 0
3 years ago
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