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bija089 [108]
3 years ago
6

How many grams of Cl are in 485g of CaCl2

Chemistry
1 answer:
Oksana_A [137]3 years ago
6 0
329g Cl (You're welcome :D)
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If 50 g of lead (of specific heat 0.11 kcal/kg ∙ C°) at 100°C is put into 75 g of water (of specific heat 1.0 kcal/kg ∙ C°) at 0
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Answer: The final temperature is 279.8K

Explanation:

heat_{absorbed}=heat_{released}

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Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

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T_2 = temperature of water = 0^oC=273K

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c_2 = specific heat of water= 1.0kcal/kg^0C

Now put all the given values in equation (1), we get

50\times 0.11\times (T_{final}-373)=-[75\times 1.0\times (T_{final}-273)]

T_{final}=279.8K

Therefore, the final temperature of the mixture will be 279.8 K.

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