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Mashcka [7]
3 years ago
7

A compound is composed of 53.33%carbon, 11.11%hydrogen and 35.56%oxygen. If the molecular mass of the compound is 90, what is th

e molecular formula of this compound?
Chemistry
1 answer:
Paraphin [41]3 years ago
7 0
The final molecular formula will be C4H10O2
Hope this helps :)

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Connectivity is an example of which type of property?​
aleksklad [387]

Answer:

physical property

Explanation:

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3 0
3 years ago
Write the word equation for this please
inna [77]

Answer:

1 mole of dinitrogen combined with 3 moles of diiodine yields 2 moles of nitrogen triiodide

Explanation:

5 0
3 years ago
In the first step of the addition reaction with HBr, the pi electrons of the double bond react with the hydrogen ion, H+, produc
Andrei [34K]

Answer:

See the figure

Explanation:

In this case, we have to take into account the <u>stability of the carbocations</u>:

Terciary>Secundary>>Primary.

In other words, is we have the <u>most substituted carbocation</u> we will have more stability. Therefore in the carbocation formation, the charge would go in the <u>most substituted carbon</u> of the double bond for each case.

8 0
3 years ago
On a cool, rainy day, the barometric pressure is 698 mmHg. Calculate the barometric pressure in centimeters of water (cmH2O). De
lesantik [10]

Answer:

Barometric pressure is 942.3 cm of column of water.

Explanation:

We can measure barometric pressure by measuring the height h of a column of fluid (this column of fluid exerts the same pressure as the column of air of which we are measuring pressure) using the following formula:

P = \rho*g*h\\

Where ρ is the density of the fluid used and g the acceleration of gravity.

Knowing that both the column of mercury (to match units, we know that 698 mmHg are the same as 69.8 cmHg) and the column of water are representing the same pressure, we can match expressions and find h for the column of water:

\rho_{Hg} *g*h_{Hg} =\rho_{Water} *g*h_{Water}\\ \\h_{Water}=\frac{rho_{Hg} *g*h_{Hg}}{\rho_{Water} *g} = \frac{13.5g/mL *9.8m/s^{2} *69.8cm}{1g/mL *9.8m/s^{2}}=942.3 cmH_{2}O

7 0
3 years ago
How many CO grans are produced from 1.80 mol of sulfur dioxide2
m_a_m_a [10]

Answer:

A mol (approximately)represents the number 6.02 X 10^^23. Mols become useful when we learn that, for any element on the periodic table, 6.02 X 10^^23 atoms of that element have a mass equal to the atomic mass in grams. So, on the periodic table carbon has an atomic mass of 12.011. That means: 12.011 grams of carbon is made up of 6.02 X 10^^23 atoms.

The above question is tricky.

If the question considers 1 molecule of SO2 as a particle, then the answer is 1.80 * 6.02 X 10^^23

If the question considers the S as one particle, and the O2 as 2 more particles, then the answer is: 3 * 1.8 * 6.02 X 10^^23.

Explanation:

hope it helps U

4 0
2 years ago
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