Answer:
25 mL of NaOH
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
Mole ratio of the acid, HCl (nₐ) = 1
Mole ratio of the base, NaOH (n₆) = 1
Finally, we shall determine the volume of NaOH required for the reaction. This can be obtained as follow:
Molarity of the base, NaOH (M₆) = 0.2 M
Molarity of the acid, HCl (Mₐ) = 0.1 M
Volume of the acid, HCl (Vₐ) = 50 mL
Mole ratio of the acid, HCl (nₐ) = 1
Mole ratio of the base, NaOH (n₆) = 1
Volume of the base, NaOH (V₆) =?
MₐVₐ / M₆V₆ = nₐ / n₆
0.1 × 50 / 0.2 × V₆ = 1
5 / 0.2 × V₆ = 1
Cross multiply
5 = 0.2 × V₆
Divide both side by 0.2
V₆ = 5/0.2
V₆ = 25 mL
Thus, 25 mL of NaOH is needed for the reaction
