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Triss [41]
3 years ago
5

What do u call a change in a state from a liquid to a gas

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
7 0
Evaporation Hope this helps,Yayi3! 
MrRissso [65]3 years ago
5 0
To make liquid a gas u have to boil it and when u boil it it's call evaporation. so your answer is evaporation
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What is Chemical Bonding?<br>Explain please.​
olga nikolaevna [1]

Answer:

Chemical bonds are how atoms, and even molecules join together.

Explanation:

There are two main types of primary chemical bonds. While secondary links relate to molecules, primary ties are atom to atom. This answer explains basic primary bonds only.

One must comprehend what a valence shell is before I proceed. The outer electron orbital of an atom is known as the valence shell. Most of the time (except from hydrogen), atoms desire to have 8 electrons in their valence shell, thus they form bonds with other atoms to accomplish this.

<em>All bonds result in a new chemically different molecule. Now, the two types are:</em>

  1. Covalent: When two atoms combine their electrons to fill their valence shells. The atoms are joined together by this "sharing."
  2. Ionic: When one atom <em>transfers</em> an electron to another atom in order to fulfill the valence electron requirement. Because electrons have a negative charge, the atom that <em>produced </em>them gains a positive charge as a result of losing its negative charge. The atom that received the electron therefore acquires a negative charge. Because opposing charges attract, it seems sense that the charged atoms bind as a result.
3 0
1 year ago
A student is interested in resource recovery through composting. Which field
sdas [7]
I think it’s microbiology, since it would help the student understand the process of composting the best. Botany is plants- not for composting. Geophysics- he’s not researching tectonic plates. Oceanography- he isn’t interested in the marina trench
4 0
3 years ago
Why can’t there be a temperature lower than absolute zero
Firdavs [7]
Atoms cannot physically get more compact (temperature lowering increases the space between atoms) At absolute zero, the atoms are as physically close together as allowed by the physical laws governing it.
7 0
3 years ago
One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K
mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (s_{2} - s_{1}), in joules per gram-Kelvin, by the following model:

s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}} (1)

Where:

m - Mass, in kilograms.

c_{w} - Specific heat of water, in joules per kilogram-Kelvin.

T_{1}, T_{2} - Initial and final temperatures of water, in Kelvin.

If we know that m = 1\,kg, c_{w} = 4190\,\frac{J}{kg\cdot K}, T_{1} = 373.15\,K and T_{2} = 288.15\,K, then the change in entropy for the entire process is:

s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}

s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0
3 years ago
What is the composition, in atom percent, of an alloy that contains a) 45.5 lbm of silver, b) 83.7 lbm of gold, and c) 6.3 lbm o
lyudmila [28]

Answer:

\% atAg=44.6\%\\\% atAu=44.9\%\\\% atCu=10.5\%

Explanation:

Hello,

In this case, for computing the atom percent, one must obtain the number of atoms of silver, gold and copper as shown below:

atomsAg=45.5lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{107.87gAg}*\frac{6.022x10^{23}atomsAg}{1molAg}=1.15x10^{26}atomsAg\\atomsAu=83.7lbm*\frac{453.59g}{1lbm}*\frac{1molAu}{196.97gAu}*\frac{6.022x10^{23}atomsAu}{1molAu}=1.16x10^{26}atomsAu\\atomsCu=6.3lbm*\frac{453.59g}{1lbm}*\frac{1molAg}{63.55gCu}*\frac{6.022x10^{23}atomsCu}{1molCu}=2.71x10^{25}atomsCu

Thus, the atom percent turns out:

\% atAg=\frac{1.15x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.6\%\\\% atAu=\frac{1.16x10^{26}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =44.9\%\\\% atCu=\frac{2.71x10^{25}}{1.15x10^{26}+1.16x10^{26}+2.71x10^{25}}*100\% =10.5\%

Best regards.

4 0
3 years ago
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