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Lesechka [4]
3 years ago
14

TRIGONOMETRY , can you solve this plz:(even if you know one of them,plz help:)​

Mathematics
1 answer:
daser333 [38]3 years ago
5 0

Answer:

See below

Step-by-step explanation:

\frac{1}{1-cos A} - \frac{1}{1+cos A} =2 cosec A cot A \\  \\ L. H. S.= \frac{1}{1-cos A} - \frac{1}{1+cos A} \\  \\ = \frac{1+cos A - (1 - cos A)}{(1-cos A)(1+cos A)}\\  \\ = \frac{1+cos A - 1  +  cos A}{1-cos^{2}  A}\\  \\ = \frac{2cos A }{sin^{2}  A}\\  \\ =2 .\frac{1}{sin A}.\frac{cos A }{sin  A}.\\  \\  = 2.cosec \: A.cot \: A \\  \\  = R.H.S

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7 0
3 years ago
AARP reported on a study conducted to learn how long it takes individuals to prepare their federal income tax return (AARP Bulle
Crank

Answer:

Confidence interval: (30.1,36.9)

Step-by-step explanation:

We are given the following data set:

35.3,30.5,37.4,26.5,13.0,49.9,28.8,44.0,61.6,0.5,40.5,34.9,47.9,36.6,24.1,39.8,47.8,18.5,36.6,39.2,14.5,37.3,40.5,49.3,45.5,28.3,19.5,5.6,52.6,41.4,45.3,39.0,33.7,29.4,14.5,40.1,33.7,36.9,5.6,33.7

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1339.9}{40} = 33.5

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n = 40

Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

33.5 \pm 1.96(\frac{11}{\sqrt{40}} ) = 6.34 \pm 3.4 = (30.1,36.9)

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3 years ago
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Answer:

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4 0
3 years ago
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