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sp2606 [1]
3 years ago
5

A rectangular picture frame is made from one-inch-wide pieces of wood. The area of just the frame is 18 square inches, and one o

f the outer edges of the frame is 5 inches long. What is the sum of the lengths of the four interior edges of the frame?

Mathematics
2 answers:
rewona [7]3 years ago
7 0

The lengths of the top/bottom interior edges are $5-2=3$ inches (since there is 1 inch of frame to either side of the interior rectangular hole). Let the lengths of the left/right interior edges be $x$ inches. Then, the lengths of the left/right exterior edges are $x+2$ inches. The area of the frame is equal to the area of the frame rectangle minus the area of the hole. This is equal to $5\cdot(x+2)-3x=2x+10$. Since we are given that this area is 18 square inches, we have the equation $2x+10=18\Rightarrow x=4$. So the dimensions of the interior hole are $3\times4$. Thus, the sum of the four interior edges is $3+4+3+4=\boxed{14}$ inches.

Leni [432]3 years ago
6 0

Answer:

46

Step-by-step explanation:

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The ratio of cats to dogs at April's Animal Shelter was 3 to 2. How many dogs were in the shleter if there were a total of 75 ca
DochEvi [55]

Answer:

A:30

Step-by-step explanation:

because 3+2(the ratio) =5

75(the total number or both) divide by 5

so 1 ratio=15

15 x 2(the ratio of dogs)

=30

3 0
2 years ago
10 points
ollegr [7]

Answer:

FC=25.9

Step-by-step explanation:

<u>Congruent Triangles</u>

The figure shows two triangles FCD and FED. One of their sides is the radius of the circle, they both form a 90° angle with the line CD and ED and they share the same segment FD.

Thus, both triangles are congruent and we have the length of a side (12 units), one common side (the hypotenuse) and one unknown leg that must be equal. Therefore

13x-16=4x+11

Solving

9x=27

x=3

The required side FD is the hypotenuse of any of the triangles. The unknown leg can be calculated by

13x-16=23

Or

4x+11=23

Thus

FD^2=12^2+23^2=673

Solving

FD=\sqrt{673}

\boxed{FC=25.9}

5 0
2 years ago
I am almost bankrupt asking the same question but....
ExtremeBDS [4]

Answer:

If you understand how I solved a you can do B. Keep at it!

Step-by-step explanation:

7 0
3 years ago
11-5 practice volumes of pyramids and cones
Minchanka [31]

Answer:

Step-by-step explanation:

Volume for a  cone =  1/3 * pi * r^{2} * h

Volume for a pyramid =  1/3 * area of base * h

4 0
2 years ago
Find the required measurements of the following trapezoids. base1 = 12 cm base2 = 14 cm height = 8 cm. compute the area. cm2
igomit [66]
The formula for the area of a trapezoid is: A= \frac{a+b}{2} h

Substitute: A= \frac{(12)+(14)}{2}(8)

Simplify: A= \frac{26}{2}(8)  \\ A= 13*8 \\ A=104

The area of the trapezoid is 104 cm.
5 0
3 years ago
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