The lengths of the top/bottom interior edges are $5-2=3$ inches (since there is 1 inch of frame to either side of the interior rectangular hole). Let the lengths of the left/right interior edges be $x$ inches. Then, the lengths of the left/right exterior edges are $x+2$ inches. The area of the frame is equal to the area of the frame rectangle minus the area of the hole. This is equal to $5\cdot(x+2)-3x=2x+10$. Since we are given that this area is 18 square inches, we have the equation $2x+10=18\Rightarrow x=4$. So the dimensions of the interior hole are $3\times4$. Thus, the sum of the four interior edges is $3+4+3+4=\boxed{14}$ inches.
I havnt done that in a while but I think you do x+105=x+95 then you add your like terms which would turn into 10=2x then you divide 10 divided by 2 which is 5, SO YOUR ANSWER IS (I think) 5x
The probability of compound events combines at least two simple events, either the union of two simple events or the intersection of two simple events.
