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3 years ago

PLZ HURRY WILL GIVE BRAINLIEST IF CORRECT

Mathematics

2 answers:

shepuryov [24]3 years ago

6 0

The answer is 19/20 Gallon

Step-by-step explanation:

So, to get the correct answer, you need to find a common denominator to be able to add the numerator and the denominator(3/4) with the other fraction(1/5).

To find the common denominator, you have to find the first number they are both equal to, which in this case, the first one is 20, so you would change both denominators in the fractions to 20.

The first fraction, 3/4, you have to multiply the 4 with the number 5 to get the answer 20, and whatever you do to the denominator you have to do with the numerator. So you would multiply 3 by 5, just as you did with 4 and get the answer of 15. So the first fraction is 15/20.

The second fraction, 1/5, you have to multiply 5 with the number 4 to get the same denominator as the first fraction, 15/20. And 5 x 4= 20, so you would change the second fraction's denominator to 20, and as I've said before: Whatever you do to the denominator, you have to do to the numerator. So you would multiply the second fraction's numerator by 4. So 1x4= 4, which makes the fraction 4/20.

So now, since you've made the denominators the same, you will have to add the numerators together: In the first fraction, 15 is your numerator while in the second fraction, 4 is your numerator. 15+4= 19.

After you add the numerators to get the answer of 19, you do not add or do anything with the denominators, they stay the same. Making the answer 19/20.

prisoha [69]3 years ago

4 0

Answer:19/20

Step-by-step explanation:

1/5 = 4/20

3/4 = 15/20

15/20 + 4/20 = 19/20

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Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

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