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balu736 [363]
4 years ago
6

ASAP PLEASE:

Mathematics
2 answers:
tester [92]4 years ago
8 0
Is think it is RS=DF
Yakvenalex [24]4 years ago
7 0

Answer:

A. \text{ Arc RS}\cong \text{Arc DF}

Step-by-step explanation:

We have been given a circle and we are told that segment RS is congruent to segment DF.

We can see that segment RS corresponds to arc RS and segment DF corresponds to arc DF.

As both segments are congruent, therefore, both arcs will be congruent as well.

We can represent this information as:

\text{ Arc RS}\cong \text{Arc DF}

Therefore, option A is the correct choice.

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I need help with number 2 please ..I will give you points
Trava [24]

Answer:83

Step-by-step explanation:d the mean you add /5= 76

There is no mode none repeat

The median put them in order get middle number. 40. 70. 83. 92. 93 is 83 best

3 0
3 years ago
0.08 is 10 times grater than
solong [7]
Subtract the minimum data value from the maximum data value to find the data range,so in this case yur data range is 

10 - 0.08 = 9.92
so yur answer is 9.92
4 0
3 years ago
How to convert improper fraction to proper fraction
Sindrei [870]

<u>Multiply the whole number by the denominator. Add the product to the numerator of the proper fraction. The sum is the numerator of the improper fraction. The denominator will stay the same.</u>

6 0
3 years ago
Find the midpoint of the segment with the following endpoints.<br> (-3,6) and (3, 0)
otez555 [7]

The midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)

<h3>Midpoint of a line </h3>

From the question, we are to determine the midpoint of the segment with the given endpoints

The given endpoints are

(-3,6) and (3, 0)

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

Thus,

The midpoint of the line with the endpoints (-3,6) and (3, 0) is

((-3+3)/2, (6+0/2)

= (0/2, 6/2)

= (0, 3)

Hence, the midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)

Learn more on Midpoint of a line here: brainly.com/question/18315903

#SPJ1

3 0
2 years ago
The center of a circle represented by the equation (x+9)^2 + (y-6)^2 =10^2 is what
inysia [295]

Answer:

A

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 9)² + (y - 6)² = 10² is in this form

with centre = (- 9, 6) → A


3 0
3 years ago
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