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JulsSmile [24]
3 years ago
11

Integers are natural numbers.

Mathematics
1 answer:
Stells [14]3 years ago
5 0

Answer: False

Step-by-step explanation:

Hope this helps

You might be interested in
If x represents a number, then write an expression for a number that is three more than the number
myrzilka [38]
Saying "a number" is the same as saying "x"

"Three more than a number" is the same as "three more than x"

If you have three more of something (say, marbles) than someone else, then you have their number of marbles plus three more.

Then, "Three more than x" is the same as "three plus x", or "3 + x"

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Students sold books to the local library as a part of a school drive. paper books were brought for $1.45 each. The library spent
nalin [4]

Answer:

213 books

Step-by-step explanation:

Paper books = $1.45 each

$ 1.45 = 1 paper book

$ 1 = 1/1.45 paper book

$98.6 = 98.6/1.45 paper books

$ 98.6 = 68 paper books

Hardback books = $ 2.25 each

$2.25 = 1 Hardbook

$1 = 1/2.25 hardbook

$ 328.10 = 328.10/2.25 hardbooks

$ 328.10 = 145.822 hard books

Number of books cannot be a decimal number, so the value has to be estimated to a nearer whole number.

$ 328.10 = 145 hard books

Total number of books bought = (145 + 68)books= 213 books (Answer)

4 0
3 years ago
Simplify (15q^6 + 5q^2)(5q^4)^-1
saveliy_v [14]

The answer should be:

3q4 + 1 /q2

6 0
3 years ago
I need help thank you
Alenkasestr [34]
Hello again! 
So just like in the last problem you would do the same here.
Solve for 3y + 6 = 3
Subtract 6 from both sides.
3y = -3
Divide by 3.
y = -1
Now plug it into 8y + 2.
8(-1) + 2 = ?
-8 + 2 = ?
= -6
I hope this helps love! :)
5 0
3 years ago
Two cars left the city for a suburb, 120 km away, at the same time. The speed of one of the cars was 20 km/hour greater than the
Virty [35]

Answer:

V1 = 60 km/h

V2 = 40 Km/h

Step-by-step explanation:

The speed of an object is defined as

Speed =  distance / time

Let

V1 be the speed of the faster car

V2 be the speed of the other car

t1 the time it took for the first car to arrive

t2 the time it took for the second car to arrive

d1 the distance traveled by first car

d2 the distance traveled by second car

We know thanks to the problem that

V1 = V2 + 20 Km/h

t1 = t2 - 1 hour

d1 = d2 = 120 Km

d1 = V1 * t1

d2 = V2* t2

V1 * t1 = V2* t2

V1* t1 = (V1 -20)*(t1 +1)

The system of equations

(V1 -20)*(t1 +1) = 120

V1 * t1 = 120

120 + (120/t1) -20*t1 = 140

(120/t1) -20*t1  = 20

Which gives,

t1 = 2

This means

V1 = 60 km/h

V2 = V1 - 20 Km/h =  40 Km/h

6 0
3 years ago
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