First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
Image B shows a reflection.
Answer:
- <u>BOX 1 </u>= 672.00
(14 * 12 = 168
168 * 4 = $ 672 )
2. <u>BOX 2</u> = 282.95
(Cell phone= $45 A MONTH
Eating outside = $50 A MONTH
12 .50 * 4 = 50 (4 WEEKS A MONTH )
Transportation = 131.2 A MONTH
32.80 * 4 = 131.2 (4 WEEKS A MONTH )
Movie = $16.75 A MONTH
Charity = $ 40 A MONTH
10 * 4 (4 WEEKS A MONTH )
<u> MONTHLY EXPENSE </u> = 45 + 50 + 131.2 + 16.75 + 40
<u> MONTHLY EXPENSE </u> = 282.95 )
3. <u>BOX 3</u> = 389.05
Money that can be saved = Monthly income - Monthly expense
Money that can be saved = 672 - 282.95
= 389.05
<h2><em>
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Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (11, 4) → x₁ = 11, y₁ = 4
Point (5, 8) → x₂ = 5, y₂ = 8
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract:

- [√Radical] Evaluate exponents:

- [√Radical] Add:

- [√Radical] Simplify:

Answer:
8
Step-by-step explanation: