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netineya [11]
3 years ago
7

A degree 4 polynomial P(x) with integer coefficients has zeros 5 i and 3, with 3 being a zero of multiplicity 2. Moreover, the c

oefficient of x^4 is 1. Find the polynomial.
Mathematics
1 answer:
Sergio039 [100]3 years ago
6 0

Multiplicity is how many times the root repeats

roots r1 and r2 of a polynomial factor to

(x-r1)(x-r2)

so 3 multiplicty 2 means (x-3)^2 is in the factorization of that polynomial


also, for a polynomial with real coefients, if a+bi is a roots, a-bi is also a root

5i is a root, therefor -5i is a root as well


roots are

(x-5i)(x+5i)(x-3)^2

if we expand

x^4-6x^3+34x^2-150x+225

the polynomial is

f(x)=x^4-6x^3+34x^2-150x+225


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Alla [95]

Answer:

0.2122\text{ ft per min}

Step-by-step explanation:

Let r be the radius ( in feet ) of the cone,

So, the diameter of the cone = 2 × radius = 2r feet,

∵ The diameter of the base of the cone is three times the height,

If h represents the height of the cone,

⇒ 2r = 3 × h,

⇒ r=\frac{3h}{2} feet,

∵ Volume of a cone,

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Where,

R = radius, H = height,

Thus, the volume of the given cone is,

V=\frac{1}{3}\pi r^2 h

=\frac{1}{3}\pi (\frac{3h}{2})^2 h

=\frac{3}{4}\pi h^3

Differentiating with respect to t ( time )

\frac{dV}{dt}=\frac{9}{4}\pi h^2\frac{dh}{dt}

We have,

\frac{dV}{dt}=6\text{ cubic ft per min},h=2\text{ feet}

6=\frac{9}{4}\pi (2)^2 \frac{dh}{dt}

6=9\pi \frac{dh}{dt}

\implies \frac{dh}{dt}=\frac{6}{9\pi }\approx 0.2122\text{ ft per min}

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Answer:

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Step-by-step explanation:

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3 years ago
1. A circle with center (-5, 2) is tangent to the y-axis. What is the radius of the circle? What is the equation of the circle?
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Answer:

Step-by-step explanation:

1)  The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis.  Thus, the radius is 5.

2)  Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given

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we see that h = 4, k = -3 and r = 6.  The center is at (4, -3) and the radius is 6.

3)  Notice that A and B have the same x-coordinate, x = 15.  The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction.   Arbitrarily choose A(15, 4) as one point on the circle.  Then the equation of this circle is

(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).

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Irina-Kira [14]

Answer:

Step-by-step explanation:

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