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Blizzard [7]
3 years ago
12

Find the output, h, when the input, x, is -18

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

The output H is 20 when the input, x, is -18

Step-by-step explanation:

H= 17 + x/6

When the input, x, is -18 then the output H will be:

H= 17 + 18/6

H= 17 + 3

H = 20

Answer: The output H is 20 when the input, x, is -18

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timama [110]
Fractions,rats, and percents all interconnect. For ext,50%=11/2 =1:2
6 0
3 years ago
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Consider a sequence defined by the recursive rule f(1) = 15; f(n)=f(n - 1) - 6 for n 2. Choose True or
Shkiper50 [21]

Answer:

The second term of the sequence is 8  False ⇒ B

The third term of the sequence is 3  True ⇒ A

The fourth term of the sequence is -3  True ⇒ A

Step-by-step explanation:

The form of the recursive rule is:

f(1) = first term; f(n) = f(n - 1) + d, where

  • f(1) is the first term
  • f(n) is the nth term
  • f(n - 1) is the term before the nth term
  • d is the common difference

∵ f(1) = 15, f(n) = f(n - 1) - 6 for n ≥ 2

∴ The first term = 15

∴ d = -6

let us find the 2nd, 3rd, and 4th terms

∵ n = 2

∴ f(2) = f(1) - 6

∵ f(1) = 15

∴ f(2) = 15 - 6 = 9

∴ The second term is 9

∴ The second term of the sequence is 8  False

∵ n = 3

∴ f(3) = f(2) - 6

∵ f(2) = 9

∴ f(3) = 9 - 6 = 3

∴ The third term is 3

∴ The third term of the sequence is 3 True

∵ n = 4

∴ f(4) = f(3) - 6

∵ f(3) = 3

∴ f(4) = 3 - 6 = -3

∴ The fourth term is -3

∴ The fourth term of the sequence is -3 True

5 0
3 years ago
Sketch a graph of the polynomial function f(x) =x3− 2x2. Use it to complete the following:
AlladinOne [14]

Answer:

We have the function:

f(x) = x^3 - 2*x^2

To sketch this, we need to graph some points, and then just draw a line that passes through the points.

The graph of this equation is shown below.

Now we can complete the question.

If the graph is below the x-axis in some interval, the function is negative in that interval

If the graph is above the x-axis in some interval, the function is positive in that interval.

If the graph goes up in a interval, then the function is increasing in that interval

If the graph goes down on an interval, then the function is decreasing in that interval.

Then:

1) f is------ on the intervals (−∞, 0) and (0, 2).

Here we can see that the graph is below the x-axis in those intervals, then here we have:

f is negative on the intervals (−∞, 0) and (0, 2).

2) f is------ on the interval (2,∞)

Here the answer is positive:

f is positive on the interval  (2,∞)

3) fi is ------ on the interval (0, 4/3)

In the graph, you can see that the graph goes down in that interval, then the correct answer here is:

f is decreasing on the interval (0, 4/3)

4) f is------ on the intervals (−∞, 0) and (4/3, ∞).

In this case, we can see that the graph goes up in these intervals, then the correct answer here is:

f is increasing on the intervals (−∞, 0) and (4/3, ∞).

5 0
3 years ago
How do you solve this problem?
yaroslaw [1]
Hope this helped! I decided to write it out for you so it would be easier to explain.

8 0
3 years ago
Find the HCF of 64 and 80.
Varvara68 [4.7K]

Answer:

64=2✖️2✖️2✖️2✖️2✖️2

80=2✖️2✖️2✖️2✖️2✖️5

Common factors=2✖️2✖️2✖️2

As HCF= Product of common factors

HCF =2✖️2✖️2✖️2

HCF=16

Step-by-step explanation:

I hope this will help you:)

7 0
3 years ago
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