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Katyanochek1 [597]
3 years ago
9

At a concession stand, 9 slices of pizza and 5 soft pretzels cost $33.25. If 6 soft pretzels and 4 slices of pizzas cost $19.50,

what is the cost of a soft pretzel and a slice of pizza?

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
8 0
Let x and y represent the costs of a pizza slice and a soft pretzel, respectively. The two purchases can be described by ...
  9x +5y = 33.25
  4x +6y = 19.50

A graph shows the solution of these equations to be
  (x, y) = (3, 1.25)

The cost of a soft pretzel is $1.25.
The cost of a slice of pizza is $3.00.

vichka [17]3 years ago
8 0
9x+5y=33.25
4x+6y=19.50
Multiply the first equation by 6 and the second one by 5 so the ys (soft pretzels) will cancel out and leave you with x (slices of pizza) so you should get:
54x+30y=199.50
20x+30y=97.50
Then subtract the equations leaving you with:
34x=102
X=3
So each piece of pizza is $3
Then plug 3 in for x to get y I’ll just use the first equation
27+5y=33.25
5y=6.25
Y=1.25
Each pretzels costs $1.25
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A town has a population of 14,000 and grows 5% every year. What will be the population after 14 years, to the nearest whole numb
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23,800 people

Step-by-step explanation:

what is 5 % of 14,000- 700( 0.05 times 14,000)

700 times 14 is 9,800

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3 years ago
A restaurant adds a 20% tip to the bills of parties of 6 or more people. Suppose a server waits on five such tables. The bill
castortr0y [4]

Answer:

$218.70

Step-by-step explanation:

You need to first convert the percentage to the decimal.

20% = 0.2

Now, you need to find 20% of each bill by multiplying each bill by 0.2.

0.2(185.45) + 0.2(205.20) + 0.2(195.05) + 0.2(245.80) + 0.2(262.00)

Because of the distributive property, you can add up the bills and multiply the sum by 0.2.

0.2(185.45 + 205.20 + 195.05 + 245.80 + 262.00)

0.2(1093.50)

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The waiter made $218.70 in tips.

4 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
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