X - 2y = -24
x - y = 4
Isolate x in the first equation by adding 2y to both sides.
x = -24 + 2y
Now plug in this value of x into the second equation.
(-24 + 2y) - y = 4
Solve. Combine all like terms, 2y - y.
-24 + y = 4
Add 24 to both sides to isolate y.
y = 28
Now plug y back into the first equation to find x.
x - 2(28) = -24
x - 56 = -24
Add 56 to both sides to isolate x.
x = 32
The solution is (32, 28).
Answer:
Step-by-step explanation:
Use synthetic division:
The coefficients of 2x^3 - 1 are {2, 0, 0, -1}. Setting up synthetic division, we get:
1 / 2 0 0 -1
2 2 2
---------------------------
2 2 2 1
Note that the remainder is 1. The same result would be obtained through long division.
The quotient is 2x^2 + 2x + 2 with a remainder of 1.
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
Angle D and angle G are the base angles, which means they are equal. If D = 18, then G = 18. Since the sum of the angles of a triangle equals 180 degrees, subtract 18 + 18 from 180 to get angle O.
180 - 36 = 144
Angle O = 144
Hope this helps =)