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Firdavs [7]
3 years ago
8

Which diagram represents a correct construction of equilateral triangle ABC, given side AB

Mathematics
1 answer:
Zinaida [17]3 years ago
6 0

No correct diagram is included in the list of choices that you have provided.

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Find the solution of this system of equations. Separate the x- and y- values with a comma. x-2y=-24 and x-y=4
defon
X - 2y = -24
x - y = 4

Isolate x in the first equation by adding 2y to both sides.
x = -24 + 2y  

Now plug in this value of x into the second equation.
(-24 + 2y) - y = 4
Solve. Combine all like terms, 2y - y.
-24 + y = 4
Add 24 to both sides to isolate y.
y = 28

Now plug y back into the first equation to find x.
x - 2(28) = -24
x - 56 = -24
Add 56 to both sides to isolate x.
x = 32

The solution is (32, 28).
6 0
3 years ago
a web designer charges a $200 fee plus $50 per hour to build a website. which equation represents the total cost, y, to a custom
dezoksy [38]
Y = 50x + 200 <=== ur equation
6 0
4 years ago
Read 2 more answers
What is the quotient when 2x^3-1 is divided by x - 1?
andrey2020 [161]

Answer:

Step-by-step explanation:

Use synthetic division:

The coefficients of 2x^3 - 1 are {2, 0, 0, -1}.  Setting up synthetic division, we get:

1    /    2    0    0    -1

                2     2    2

    ---------------------------

          2     2    2     1

Note that the remainder is 1.  The same result would be obtained through long division.

The quotient is 2x^2 + 2x + 2 with a remainder of 1.  

4 0
3 years ago
How to find upper and lower bound of a definite integral given an unknown equation?
worty [1.4K]
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of  definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this 

\int\limits^6_1 t^{2} - 6t + 11dt 

So, i integrate this, 
( \frac{t^{3} }{3} - 3t^{2} + 11t) \int\limits^6_1

I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
4 0
3 years ago
help me its easy Triangle DOG is an isosceles triangle with DO = OG, and mD = 18. What is mO? A. 18 B. 36 C. 144 D. 162
S_A_V [24]
Angle D and angle G are the base angles, which means they are equal. If D = 18, then G = 18. Since the sum of the angles of a triangle equals 180 degrees, subtract 18 + 18 from 180 to get angle O.
180 - 36 = 144
Angle O = 144

Hope this helps =)
4 0
3 years ago
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