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bagirrra123 [75]
3 years ago
9

(x^3+6x^2-8x-43)/(x+2) dividing polynomials

Mathematics
1 answer:
Bess [88]3 years ago
4 0
X^2 + 4x - 16 - 11/(x + 2)
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C=100+25h solve for h
aivan3 [116]

Answer:

h=(c/25)-4

Step-by-step explanation:

c-100 = 25h.   "/25"

(c/25)-4 = h

7 0
3 years ago
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What is ___x5=20 3x _____=6 2+ ____=16 3x____=24 9x____=34 12+____=2
nydimaria [60]

Answer:

4×5=20

3×2=6

2+14=16

3×8=24

9×4=36, 36 -2 = 34

12+(-10) =2

4 0
2 years ago
Which is a correct expansion of (4x + 1)(2x - 2)?​
bekas [8.4K]

Answer:

8x^2 -6x-2

Step-by-step explanation:

formula= ab^2(- or +)b-ab

3 0
3 years ago
Taxes on the property buyer Tamara is purchasing are $8,200, due on December 31. If the closing is set for June 29th, using the
rosijanka [135]

The buyer will be paying taxes for 185 days, so will pay

... (185/365)·$8200 = $4156

Your most appropriate choice seems to be $4178, which corresponds to 186 days' taxes.

_____

There are 30 days in each month in the last half of the year, plus 1 additional day in each of July, August, October, and December. The 30th of June also belongs to the buyer (but the 29th, closing day, does not), so there are 180+5 = 185 days for which the buyer must pay taxes. The answer choices don't include that value.

3 0
3 years ago
(4x-9)(2x^2+2x+1) (4x−9)(2x 2 +2x+1)
tia_tia [17]

Answer:

(4x-9)^2*(2x^2+2x+1)^2

Step-by-step explanation:

(((4x-9)•(((2•(x2))+2x)+1))•(4x-9))•((2x2+2x)+1)

]  (((4x-9)•((2x2+2x)+1))•(4x-9))•(2x2+2x+1)

Trying to factor by splitting the middle term

Factoring  2x2+2x+1

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   2 • 1 = 2

Step-2 : Find two factors of  2  whose sum equals the coefficient of the middle term, which is   2 .

     -2    +    -1    =    -3

     -1    +    -2    =    -3

     1    +    2    =    3

     2    +    1    =    3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

 ((4x-9)•(2x2+2x+1)•(4x-9))•(2x2+2x+1)

Multiplying Exponential Expressions:

4.1    Multiply  (4x-9)  by  (4x-9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (4x-9)  and the exponents are :

         1 , as  (4x-9)  is the same number as  (4x-9)1

and   1 , as  (4x-9)  is the same number as  (4x-9)1

The product is therefore,  (4x-9)(1+1) = (4x-9)2

Trying to factor by splitting the middle term

5.1     Factoring  2x2+2x+1

The first term is,  2x2  its coefficient is  2 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   2 • 1 = 2

Step-2 : Find two factors of  2  whose sum equals the coefficient of the middle term, which is   2 .

     -2    +    -1    =    -3

     -1    +    -2    =    -3

     1    +    2    =    3

     2    +    1    =    3

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Multiplying Exponential Expressions:

5.2    Multiply  (2x2+2x+1)  by  (2x2+2x+1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2x2+2x+1)  and the exponents are :

      1 , as  (2x2+2x+1)  is the same number as  (2x2+2x+1)1

and   1 , as  (2x2+2x+1)  is the same number as  (2x2+2x+1)1

The product is therefore,  (2x2+2x+1)(1+1) = (2x2+2x+1)2

Final result :

 (4x - 9)2 • (2x2 + 2x + 1)2

6 0
2 years ago
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