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Contact [7]
3 years ago
6

If a geometric sequence has a2 = 495 and a6 = 311, approximate the value of the common ratio ???? to four decimal

Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

r = 0.8903

Step-by-step explanation:

given,

a₂ = 495

a₆ = 311

geometric  sequence formula

                       a_n = ar^{n-1}

                       a_2 = ar^{2-1}

                       a_2 = ar...................(1)

                       a_6 = ar^{6-1}

                       a_6 = ar^5................(2)

dividing equation (2) by (1)

                     \dfrac{a_6}{a_2} = \dfrac{ar^5}{ar}

                     \dfrac{311}{495} = r^4

                     r^4 = 0.628

                     r = 0.8903

hence, the common ratio of the geometric sequence is r = 0.8903

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