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Lapatulllka [165]
3 years ago
6

Y+4= 2/3 (x+3) written in standard form​

Mathematics
2 answers:
Kay [80]3 years ago
5 0

Answer:

2x−3y = 6

(i think)

Step-by-step explanation:

mamaluj [8]3 years ago
3 0
2x-3y=6 is correct:)
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INEQUALITIES.<br> 18.<br> 10 - X &lt; 35
irina [24]

Answer:

-25

Step-by-step explanation:

First subtract 10 from 35 which gives you 25 then ÷ 25 by -1x which gives you -25

8 0
3 years ago
Each of 100 people receives a random item from a grocery store and assigns it a value between 1 (low) and 10 (high). They trade
belka [17]

Answer:

The answer is "After trading, the value would be higher because preferences are diverse".

Step-by-step explanation:

Every person receives a resulting in the possibility from either a grocery shop and gives a value of from 1 to 10. (high). Participants trade these goods with each other for items that prefer to receive randomly but instead assign a second value to the object that finishes after the trade is concluded (1 to 10 again). Its value would've been higher after trading because the total of those before trading choices is unique compared to an exchange sum.

3 0
2 years ago
Complete the table for each function. then answer the questions that follow.
vekshin1

Answer:

a.) 4

b.) 4

c.) 8

d.) 16

e.) 12

f.) 36

g.) 64

7 0
2 years ago
83,277 round it up to the nearest thousand
erica [24]
83,000 since 277 is not near another 1,000
5 0
3 years ago
In a recent year, the ACT scores for the math portion of the test were normally distributed, with a mean of 21.1 and a standard
Natali5045456 [20]

Answer:

a) P(X

And we can find this probability using the normal standard table or excel:

P(z

b) P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

c) P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

d) We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(21.1,5.3)  

Where \mu=21.1 and \sigma=5.3

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Part b

P(19

And we can find this probability with this difference:

P(-0.396

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-0.396

Part c

P(X>26)=P(\frac{X-\mu}{\sigma}>\frac{26-\mu}{\sigma})=P(Z>\frac{26-21.1}{5.3})=P(z>0.925)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.925)=1- P(Z

Part d

We can consider unusual events values above or below 2 deviations from the mean

Lower = \mu -2*\sigma = 21.1 -2*5.3 =10.5

A value below 10.5 can be consider as unusual

Upper = \mu +2*\sigma = 21.1 +2*5.3 =31.7

A value abovr 31.7 can be consider as unusual

6 0
3 years ago
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