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4 years ago

Make m the subject in a(c+m)=2(c+3m)

Mathematics

1 answer:

Murrr4er [49]4 years ago

3 0

Answer:

m = $\frac{2c-ac}{a-6}$

Step-by-step explanation:

distribute parenthesis on both sides

ac + am = 2c + 6m ( collect terms in m on left side )

subtract 6m from both sides

ac + am - 6m = 2c ( subtract ac from both sides )

am - 6m = 2c - ac ( factor left side )

m(a - 6) = 2c - ac ( divide both sides by (a - 6))

m = $\frac{2c-ac}{a-6}$

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Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95

Virty [35]

Answer:

$L(x)=1+\dfrac{1}{3}x$

$\sqrt[3]{0.95} \approx 0.9833$

$\sqrt[3]{1.1} \approx 1.0333$

Step-by-step explanation:

Given the function: $g(x)=\sqrt[3]{1+x}$

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial, $L(x)=f(a)+f'(a)(x-a)$

a=0

$g(0)=\sqrt[3]{1+0}=1$

$g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}$

Therefore:

$L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x$

(b) $\sqrt[3]{0.95}= \sqrt[3]{1-0.05}$

When x = - 0.05

$L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833$

$\sqrt[3]{0.95} \approx 0.9833$

(c)

(b) $\sqrt[3]{1.1}= \sqrt[3]{1+0.1}$

When x = 0.1

$L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333$

$\sqrt[3]{1.1} \approx 1.0333$

7 0

3 years ago

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. Find the remainder

victus00 [196]

Answer:

Step-by-step explanation:

Given:

(h⁴ + h² – 2) ÷ (h + 3).

We could obtain the remainder using the remainder theorem :

That is the remainder obtained when (h⁴ + h² – 2) is divided by (h + 3).

Using the reminder theorem,

Equate h+3 to 0 and obtain the value of h at h+3 = 0

h + 3 = 0 ; h = - 3

Substituting h = - 3 into (h⁴ + h² – 2) to obtain the remainder

h⁴ + h² – 2 = (-3)⁴ + (-3)² - 2 = 81 + 9 - 2 = 88

Hence, remainder is 88

4 0

3 years ago

Please help. Write the equation of the graph. (Do not use spaces. Use ^ to represent exponents. Example 2^3 is 23.)

lana66690 [7]

This graph has a horizontal asymptote so it is an exponential graph. It also passes through two points (0,-2) and (1,3). The horizontal asymptote is at y=-3.
The unchanged exponential equation is y=a(b)^x +k
For exponential equations, k is always equal to the horizontal asymptote, so k=-3.
You can check this with the ordered pair (0,-2). After that plug in the other ordered pair, (1,3).
This gives you 3=a(b)^1 or 3=ab. If you know the base the answer is simple as you just solve for a.
If you don't know the base at this point you have to sort of guess. For example, let's say both a and b are whole numbers. In that case b would have to be 3, as it can't be 1 since then the answer never changes, and a is 1. Then choose an x-value and not exact corresponding y-value. In this case x=-1 and y= a bit less than -2.75. Plug in the values to your "final" equation of y=(3)^x -3.
So -2.75=(3^-1)-3.
3^-1 is 1/3, 1/3-3 is -8/3 or -2.6667 which is pretty close to -2.75. So we can say the final equation is y=3^x -3.
Hope this helps! It's a lot easier to solve problems like these given either more points which you can use system of equations with, or with a given base or slope.

7 0

3 years ago

Work out the area of this circle. Give you answer in terms of pi and state it’s units

tino4ka555 [31]

Answer:

49π

Step-by-step explanation:

area of circle = πr^2

<em>Handy Tip: cherry pies delicious; apple pies are(R) too(2)! so C = πd and A = πr^2</em>

diameter = 14 cm

radius = 14/2 = 7cm

area of circle = π(7)^2

area of circle = 49π

Hope that helps!

3 0

3 years ago

Which factor contributed to the growth of the us economy during the 20 century?

Sphinxa [80]

The United States increased its global influence.

7 0

3 years ago