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lilavasa [31]
4 years ago
5

Make m the subject in a(c+m)=2(c+3m)

Mathematics
1 answer:
Murrr4er [49]4 years ago
3 0

Answer:

m = \frac{2c-ac}{a-6}

Step-by-step explanation:

distribute parenthesis on both sides

ac + am = 2c + 6m ( collect terms in m on left side )

subtract 6m from both sides

ac + am - 6m = 2c ( subtract ac from both sides )

am - 6m = 2c - ac ( factor left side )

m(a - 6) = 2c - ac ( divide both sides by (a - 6))

m = \frac{2c-ac}{a-6}


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The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees. If we want to be 90% c
siniylev [52]

Answer:

19 beers must be sampled.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The population standard deviation for the temperature of beers found in Scooter's Tavern is 0.26 degrees.

This means that \sigma = 0.26

If we want to be 90% confident that the sample mean beer temperature is within 0.1 degrees of the true mean temperature, how many beers must we sample?

This is n for which M = 0.1. So

M = z\frac{\sigma}{\sqrt{n}}

0.1 = 1.645\frac{0.26}{\sqrt{n}}

0.1\sqrt{n} = 1.645*0.26

\sqrt{n} = \frac{1.645*0.26}{0.1}

(\sqrt{n})^2 = (\frac{1.645*0.26}{0.1})^2

n = 18.3

Rounding up:

19 beers must be sampled.

7 0
3 years ago
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Answer:14/15 + 42/11

Step-by-step explanation:

4 0
3 years ago
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Ket [755]

Answer:

D

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8 0
4 years ago
Janet and Nadia each play basketball, Nadia has won twice the number of games Janet has, Is it possible for Janet to have won 10
Lapatulllka [165]

Answer:

It is not possible for Janet to have won 10 games.

Step-by-step explanation:

Let be "x" the number of games Janet won.

We know that Nadia has won twice the number of games Janet has and the sum of the games Nadia and Janet have won together is 24.

Then, we express this situation with this equation:

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Therefore, it is not possible for Janet to have won 10 games.

4 0
3 years ago
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