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aleksley [76]
3 years ago
12

Janet and Nadia each play basketball, Nadia has won twice the number of games Janet has, Is it possible for Janet to have won 10

games if the sum of the games
Nadia and Janet have won together is 24?
Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

It is not possible for Janet to have won 10 games.

Step-by-step explanation:

Let be "x" the number of games Janet won.

We know that Nadia has won twice the number of games Janet has and the sum of the games Nadia and Janet have won together is 24.

Then, we express this situation with this equation:

So, let's check if it is possible for Janet to have won 10 games. Substitute  into the expression:

Therefore, it is not possible for Janet to have won 10 games.

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I mean based on your possible answers, the third one is correct,but you can go further that that, in the steps i will note when you've came to the "answer"

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\frac{x + 2}{ {x}^{2} + 2x - 5x - 10 }  \times  \frac{x - 3}{ {x}^{2} + 4x - 3x - 12 }
\frac{x + 2}{x(x + 2) - 5(x + 2)}  \times  \frac{x - 3}{x(x + 4) - 3(x + 4)}
\frac{x + 2}{(x + 2) \times (x - 5)}  \times  \frac{x - 3}{(x + 4) \times (x  - 3)}
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and basically that's the "answer", but you can simplify more.

\frac{1}{ {x}^{2}  + 4x - 5x - 20}
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