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bezimeni [28]
3 years ago
6

Jackie is planning a surprise birthday party for her best friend and is researching a location to have the party. Jackie found a

great location, but they are requesting that she send her personal information over the internet. What should Jackie do?
A) Ignore the request and not enter any personal information.
B)Provide only her name and date of birth.
C) Provide only her name and address.
D) Provide the requested information.

PLS HELP ASAP
Computers and Technology
1 answer:
topjm [15]3 years ago
5 0

Answer:

A

Explanation:

She is going to get scam

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
2 years ago
You complete your database, and the company begins using it. Shortly afterwards, two GearUp buyers, Cora and Owen, work together
Olegator [25]

Answer: Multi-user issue

Explanation: A database management system scheme can have multi-user issue when the designing of the system is not made properly. The multi user issue rises when the users concurrently access the data from the database and related error get invoked due to some reason like  repeatable reading issue, serialization, etc.

The reading problem is usually can be related to reading of the database in  uncommitted manner, uncommitted reading, repeatedly reading etc.Thus, Cora and Owen are accessing the database concurrently which can create multi-user issue.

3 0
3 years ago
Which statement will remove 5:'softball' from the dictionary?
dimaraw [331]

Answer:

sports.pop(5)

Explanation:

edg 2020

4 0
3 years ago
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____ map a set of alphanumeric characters and special symbols to a sequence of numeric values that a computer can process.
Neporo4naja [7]
The answer is : coding schemes
4 0
3 years ago
Is the following a true statement in our world? Why or why not?
posledela

Answer:

The statement would be true

.

Explanation:

let,  L = is a NFL player

      M = teaches in CSU

      N = has tattoos

Given that:

nfl player who teaches in csu = L^ M                 (this is false every time)

Above statement is L ^ M -> N

this would be true because

false -> true                  (true

)

false -> false                  (true

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Second  exp:

There are no players who teach in Csu therefore if we say they all have tattoos statement would be true.

4 0
3 years ago
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