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Alex787 [66]
3 years ago
6

How do you solve for x in this problem?

Mathematics
2 answers:
madam [21]3 years ago
8 0

Yo sup??

You can solve this problem by applying the cosine rule ie

a²=b²+c²-2bccosx

x²=11²+8²-2*11*8cos16

=121+64-169.2

=15.8

x=√15.8

=4  (approx)

Hope this helps.

irina [24]3 years ago
4 0

Answer: you will use the cosine rule

Step-by-step explanation:

x^2=11^2+8^2-2(11)(8)xcos(16)

x^2=185-169.18

x^2=15.8

Take square root

x=3.96 or 4

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I would compute sqrt(1 + 160pi^2) first to get approximately 39.75093337

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In short, I computed \frac{1+\sqrt{1+160\pi^2}}{2\pi} only focusing on the plus for now.

----------------------

If you were to compute \frac{1-\sqrt{1+160\pi^2}}{2\pi} you should get roughly -6.167402596 as your other solution. Each solution can then be plugged into the original equation to check if you get 0 or not. You likely won't land exactly on 0 but you'll get close enough.

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