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Sergeu [11.5K]
3 years ago
12

The height and diameter of a cone-shaped storage tank are 9 feet (height) and 14 feet

Mathematics
1 answer:
lana [24]3 years ago
3 0

Answer: 461.60 is the volume of liquid the tank can hold.

Step-by-step explanation:

We were given;

Height H = 9 ft

Diameter D = 14 ft

Pie π = 3.14

We will make use the formula of volume of a cone to get volume of water the tank can hold because it is said that the tank is in the shape of a cone

So

V = 1/3 * πr2h

First we need to find our radius r

Radius = 1/2 of diameter = 14/2 = 7

So using the formula

V = 1/3 * πr2h

V = 1/3 (3.14 * 7² * 9)

V = (3.14 * 49 * 9)/3

V = 1384.74 / 3

V = 461.58 = 461.60 (nearest ten)

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Step-by-step explanation:

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Find an equation of the plane that is parallel to the xz-plane and is located 11 units to the right of the xz-plane in standard
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Answer:

y = 11

Step-by-step explanation:

Since our plane is parallel to the xz plane, the x and z are independent of each other, i.e. they could be anything. So xz plane has an equation of y = 0. So if this plane is located 11 units to the right of the xz plane then its equation must be y = 11.

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7 more than 5 times a number is 122
Luba_88 [7]

Answer:

The number is 23.

Step-by-step explanation:

5n + 7 = 122               Subtract 7 on both sides

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        n = 23

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3 years ago
Anne, Barry, and Cathy enter a coffee shop. Anne orders two coffees, one juice, and two doughnuts and pays $7.50. Barry orders o
Evgesh-ka [11]

Answer:

Coffee = $2.00

Juice = $1.50

Doughnut = $1.00

Step-by-step explanation:

Given

Let:

c = coffee\\ j= juice\\ d = doughnut

So, we have:

Anna

2c + j + 2d = 7.50

Barry

c + 3d = 5.00

Cathy

3c + j + 4d = 11.50

Required

The price of each

We have:

2c + j + 2d = 7.50

c + 3d = 5.00

3c + j + 4d = 11.50

Make c the subject in: c + 3d = 5.00

c = 5.00 - 3d

Substitute c = 5.00 - 3d in 2c + j + 2d = 7.50 and 3c + j + 4d = 11.50

2c + j + 2d = 7.50

2[5.00 - 3d] + j + 2d = 7.50

10.00 - 6d+ j + 2d = 7.50

Make j the subject

j = 7.50 - 10.0 +6d - 2d

j = -2.50 +4d

3c + j + 4d = 11.50

3[5.00 - 3d] + j + 4d = 11.50

15.00 - 9d + j + 4d = 11.50

Make j the subject

j = 11.50 - 15.00 + 9d -4d

j = -3.50 + 5d

So, we have:

j = -3.50 + 5d and j = -2.50 +4d

Equate both values of  j

-3.50 + 5d = -2.50 + 4d

Collect like terms

5d - 4d = 3.50 -2.50

d = 1.00

Substitute d = 1.00 in j = -3.50 + 5d

j = -3.50 + 5d

j = -3.50 + 5 * 1.00

j = -3.50 + 5.00

j = 1.50

To solve for c, we substitute d = 1.00 in c + 3d = 5.00

c + 3 * 1.00 =5.00

c + 3.00 =5.00

Solve for c

c =- 3.00 +5.00

c =2.00

7 0
2 years ago
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