Series = <span>{2, 5 ,6, 7, 15, 16, 17}
Here, Median = 7
Then Q3 = </span><span>{15, 16, 17}
Median of Q3 = 16
In short, Your Answer would be: 16
Hope this helps!</span>
Difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
recognize that
(2x+1)(2x-1)
(a+b)(a-b)
therefor
product is
(2x)^2-(1)^2=
4x^2-1
Step-by-step explanation:
area of circle - pie x r x r
22/7 x 7/2 x 7/2 ( 7 as diameter because it's straight line passing through centre)
77/2 is the sq inches
7y-3°=3y+13°
7y-3y= 13°+3°
4y= 16°
y=4°
Substitute y
7(4)-3°= 25°
3(4)+13=25°
180°-25°-25°=130°
2(2x+3)°+130°=180°
4x+136°=180°
4x=44°
x=11°
Answer:
z = 2.1784 > 1.96,
Reject the null hypothesis
Step-by-step explanation:
For the males:
n1 = 162, x1 = 63
P1 = x 1/ n1 = 0.3889
For the Females:
n2 = 333,
x2 = 97
P 2 = x2/n2
= 0.2913
P 1= P2 Null hypothesis
P 1 is not equal to P 2 alternative hypothesis
Pooled proportion:
P= (x1 + x2) /( n1+ n2)
= (63 + 97) / (162 + 333)= 0.3232
Test statistics :
Z= (p1 - p2) /√p(1-p)× (1/n1 + 1/n2)
0.3889- 0.2913 / √0.3232 × 0.6768 × (1/162 +1/333)
=2.1784
c) Critical value :
Two tailed critical value, z critical = Norm.S .INV (0.05/2) = 1.960
Reject H o if z < -1.96 or if z > 1.96
d) Decision:
z = 2.1784 > 1.96,
Reject the null hypothesis
