P parallel to q
So m<1 =m <3
3x=105
x=35
tell me if you don't understand
here,
2x-6y= -12
2(x-3y)= -12
x-3y = -6...........eq1
x+2y=14............eq2
we can subtract the above two given equations
we get,

___________

so,
y=4
now to find the value of x we have to substitute the value of y in any of the above two equations, I choose eq2
we get,

<h3>so,</h3><h3> x=6,y=4</h3>
Answer:

Step-by-step explanation:
Evaluate g(- 4) and f(- 4) by substituting x = - 4 into g(x) and f(x), that is
f(- 4) = - 10(- 4) + 9 = 40 + 9 = 49
g(- 4) = (- 4)² + 12 = 16 + 12 = 28
Then
=
= 
Hello,
P(x)=x^3-7x-6
P(4)=4^3-7*4-6=30
Remainder=30
The antiderivate of 5x is 5x^2 / 2 .