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2 years ago

WILL GIVE BRAINLIEST TO RIGHT ANSWER!!

Mathematics

2 answers:

Sati [7]2 years ago

8 0

2.Corresponding Angles theorem

6.Transitive Property

8.Triangle Proportionally Theorem

daser333 [38]2 years ago

3 0

Answer:

Step-by-step explanation:

2 - Corresponding angles theorem

6 - Alternate exterior angles theorem

8 - Transitive Property

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-10 +log3 (n+3)= -10

Rufina [12.5K]

Answer:

n= -3 or in exact form: N= - log27/log3

Step-by-step explanation:

8 0

3 years ago

Make D the subject of S=D/T<br> You may use the flowchart to help you if you wish.

hammer [34]

Given the equation, S = D/T:

To make the D the subject of the equation, we can start by multiplying both sides by T to isolate D:

(T) S = D/T (T)

TS = D

Therefore, the final answer is D = TS

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2 years ago

Find the volume of a spere with radius of 7

choli [55]

Formula for volume of sphere V = 4/3 (Pi) r^3, where Pi ~ 3.14 and r is the radius = 7.

Therefore V = 4/3 * 3.14 * 7^3

= 4/3 * 3.14 * 343

= 4/3 * 1077.02

= 1,436.02667 cubic units

6 0

2 years ago

Read 2 more answers

An open box is to be constructed so that the length of the base is 3 times larger than the width of the base. If the cost to con

natta225 [31]

Answer:

Step-by-step explanation:

Let assume that the volume = 88 cubic feet

Then:

$L = 3w --- (1)volume = l \times w \times h \\ \\ 88 = (3w) \times w \times h \\ \\ 3w^2 h= 88 \\ \\ h = \dfrac{88}{3w^2}--- (2) \\ \\$

The construction cost now is:

$C = 4(l \times w) + 2 ( w \times h) + 2(l \times h) \\ \\ C = 4(3w^2) + 2(w \times \dfrac{88}{3w^2}) + 2(3w \times \dfrac{88}{3w^2}) \\\\ C = 12w^2 + \dfrac{176}{3w} + \dfrac{176}{w}$

Now, to determine the minimum cost:

$\dfrac{dC}{dw}= 0 \\ \\ \implies 24 w - \dfrac{176}{3w^2}- \dfrac{176}{w^2}=0 \\ \\ 24 w ^3 = \dfrac{176}{w^2}(\dfrac{1}{3}+1) \\ \\ 24 w ^3 = \dfrac{176(4)}{3} \\ \\ w^3 = \dfrac{88}{3(3)}$

$w = \dfrac{88}{3(3)}^{1/3} \ feet$

Now;

$length = 3 ( \dfrac{88}{3(3)})^{1/3} \ feet$

$height = ( 88})^{1/3} (3)^{1/3} \ feet$

6 0

2 years ago

Find the maclaurin series for f(x) using the definition of a maclaurin series. [assume that f has a power series expansion. do n

Nady [450]

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

The maclaurin series for f(x) is defined by the following formula:

$f(x) = \sum_{i=0}^{\infty} \frac{f^{(i)} (0)}{i!} .x^{i}$ --------------(1)

Where $f^{i}$ is the i - th derivative of the function

If f(x) = $e^{-6x}$ , then the formula of the i - th derivative of the function is:

$f^{i} =(-6)^{i} .e^{-6x}$ ----------------------(2)

Then,

$f^{i}(0) = (-6)^{i}$

Lastly, the equation of the trascendental function by Maclaurin series is: $f(x)=\sum_{i=0}^{\infty} \frac{(-6)^{i}.x^{i} }{i!} \\f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ ---------------(3)

Hence,

The equation of $f(x) = e^{-6x}$ by maclaurin series is $f(x)=\sum_{i=0}^{\infty} \frac{(-6.x)^{i} }{i!}$ .

Find out more information about maclaurin series here

brainly.com/question/24179531

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4 0

10 months ago