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Fed [463]
3 years ago
10

ALGEBRA NATION Question 5 of 10 < Previous Question Next Question > Rewrite the expression below. -2a(a + b – 5) + 3(-5a +

2b) + b(6a + b – 8)
Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0

–2a² + 4ab – 5a – 2b + b²

Solution:

Given data:

–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)

<u>To solve this expression:</u>

Multiply each number or variable into the bracket.

–2a(a + b – 5) + 3(–5a + 2b) + b(6a + b – 8)

        = –2a² – 2ab + 10a – 15a + 6b + 6ab + b² – 8b

Arrange like terms together.      

       = –2a² – 2ab + 6ab + 10a – 15a + 6b – 8b + b²

       = –2a² + 4ab – 5a – 2b + b²

Hence the solution is  –2a² + 4ab – 5a – 2b + b².

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Someone do this and show the work !!! Please help :)
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write a polynomial function of least degree with integral coefficients having zeros that include -1 and 1 + 2i
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