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Iteru [2.4K]
3 years ago
15

Could someone help me with this plz. That would be great. You get points

Mathematics
1 answer:
GREYUIT [131]3 years ago
8 0

Answer:

C

Step-by-step explanation:

i may be wrong sorry

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The following polynomial has factors (x + 8) and (3x + 2). Determine the value of k. −6x^3-55x^2+kx−16
RoseWind [281]

Answer:

<h2>k = - 58</h2>

Step-by-step explanation:

Since (x + 8) and (3x + 2) are factors of the polynomial it means that if either one of them is equated to zero and substituted into the polynomial will give us zero

Using x + 8

We have

x + 8 = 0

x = - 8

Substitute the value of x into the polynomial

- 6x³ - 55x² + kx - 16

That's

- 6(-8)³ - 55(-8)² + k(-8) - 16 = 0

-6(-512) - 55(64) - 8k - 16 = 0

Expand

3072 - 3520 - 8k - 16 = 0

Simplify

- 464 - 8k = 0

8k = -464

Divide both sides by 8

k = - 58

Hope this helps you

6 0
2 years ago
PLEASE HELP!!!!
den301095 [7]

Answer:

multiplication

Step-by-step explanation:

7 0
2 years ago
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Which of the three runners have the fastest pace? Explain how you know.
GenaCL600 [577]
What is the image, i can’t see it?
6 0
3 years ago
Write the trigonometric expression <br> Cos (arcsin (u))<br> As an algebraic expression in u
makvit [3.9K]
When we use arcsine, we are finding the angle while giving the trigonometric ratio.

Arcsin(u) = theta can be rewritten as:

sin(theta) = u

Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.

We can use Pythagorean Theorem to find the adjacent (x value).

1^2 - u^2 = x^2

x = sqrt(1-u^2)

Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).

Cosine is adjacent over hypotenuse.

So our answer is sqrt(1-u^2)/1

Or just sqrt(1-u^2)







5 0
3 years ago
This is due in 15 minutes pls help me lol thx
GaryK [48]

Answer:

ITS A

Step-by-step explanation:

PLZ GIVE BRAINLEIST

7 0
2 years ago
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