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andre [41]
4 years ago
13

Problem page a pipe is 30 feet long. it needs to be cut into pieces that are each 23 feet long. how many pieces can be made from

the pipe?
Mathematics
2 answers:
wariber [46]4 years ago
8 0

Answer:

You can only make one piece of that pipe.

Step-by-step explanation:

To find this, take the total amount of pipe and divide it by the section that you need.

30ft/23ft = 1.3 pieces

Since .3 pieces is not a full piece, we disregard that amount and say that you can only make one piece.

Colt1911 [192]4 years ago
6 0
Only 1 pice can be made with the pipe.
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What is 2(x-2)+x eqaul
Rzqust [24]

Answer:

3x-4

Step-by-step explanation:

4 0
3 years ago
What is the answer to -8x-9>-21
dybincka [34]
<h3>:- Solution</h3>

-8x - 9 > -21

Move -9 to right side

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-8x > -12

x < -12/-8

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the answer to -8x - 9 > -21 is <u>x</u><u> </u><u><</u><u> </u><u>3</u><u>/</u><u>2</u>

3 0
3 years ago
Given:
Fynjy0 [20]

Answer:

Option B is correct.

\triangle RST \cong \triangle TUR  

Step-by-step explanation:

Given: RSTU is a parallelogram.

By definition of parallelogram, two pairs of opposite sides are congruent in length.

⇒TU \cong RS and TS \cong RU

In triangle RST and  triangle TUR

RS \cong TU  [Side]  

TS \cong RU  [Side]

RT \cong RT   [Common side]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of other triangle, then the triangles are congruent.

then, by SSS postulates we have;

\triangle RST \cong \triangle TUR    


5 0
4 years ago
The hawaiian alphabet has 12 letters. How many permutations are possible for five of these letters
guajiro [1.7K]

Answer: The answer is 50980

Step by Step Explanation:

First, temporarily assume that two letters with I are different, call them i 1 and i 2. Three "a" are also called as a 1, a 2 and a 3, and two h as h 1 and h 2. Then there are 11 * 10 * 9 * 8 * 7 = 55440 possible "words" (one of 11 is the first letter, 10 is the second, and so on). But because equal letters do the same "words," some "words" were counted twice or more. We have to deduct the number of "parasitic" counts although it is fairly small. The words that counted more than once are divided into many disjoint sets: 1) with two I but without repetitions of a and h; 2) with two h but without repetitions of a and I 3) with two a but without repetitions of I and h; 4) with three a but without repetitions of I and h; 5) with two I and two a's; 6) two i's and tree a's; 7) two i's and two h's 8) two h's and two a's; 9) two h's and one tree. The first category includes terms counted twice and its scale is (5 * 4) * (6 * 5 * 4) = 2400 (the first I stays at one of the 5 positions, the second at one of the 4, then 11-2i-1h-2a=6). So we have 2400/2 = 1200 to subtract. Group 2 gives -600 as well, and group 3 also. Group 4 gives * (6 * 5) = 1800 (5 * 4 * 3), and the terms are counted 6 times, -300. Groups 5, 7 , 8: 5 * 4 * 3 * 2 * 6 = 720 and counted four times, therefore -180. Group 6 and 9: 5 * 4 * 3 * 2 * 1 = 120, with 12 counts, -10. Altogether -(1200 * 3 + 300 + 180 * 3 + 10 * 2) = -4460.The answer will be 55440-4460 = 50980.

3 0
4 years ago
Solve for (x): (14.5x − 5(x + 2) ≤ 4 + 4(4 − 1/8x)
Helen [10]

Answer:x ≤ 3

Step-by-step explanation:

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9.5x-10 ≤ 20-1/2x Combine like terms

10x - 10 ≤ 20

10x/10 ≤ 30/10

x ≤ 3

5 0
3 years ago
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