Remember that pi=180,
so 180/6=30, 30*5=150,
what's tan 150?
Remember that 150 degrees is in the 2nd quadrant, and this is tangent, so it means the answer must be negative, because tan 150= - tan 30, and -tan30=-√3/3.
Answer: -√3/3.
Answer:
a c
Step-by-step explanation:
To complete the square you halve the coefficient of the x term and square it. Half of 14 is 7 and 7² is 49. So we add 49 and subtract 49, which means we are not changing the value of the quadratic. So we have x²+14x+49-49+2. This can be written: (x²+14x+49)-49+2, which is (x+7)²-47, which is answer a.
The monthly amortization is P23,511.63
<h2>Compound interest</h2>
The formula for calculating the compound interest is expressed as:
![A = P(1+r/n)^t](https://tex.z-dn.net/?f=A%20%3D%20P%281%2Br%2Fn%29%5Et)
whrere:
- P is the principal = P700,000
- r is the rate = 12% = 0.12
- t is the time = 4 years
- n = 12
Substitute the parameters
![A = 700000(1+0.12/12)^{4(12)}\\ A = 700,000(1.01)^{48}\\ A =1,128,558.25](https://tex.z-dn.net/?f=A%20%3D%20700000%281%2B0.12%2F12%29%5E%7B4%2812%29%7D%5C%5C%0AA%20%3D%20700%2C000%281.01%29%5E%7B48%7D%5C%5C%0AA%20%3D1%2C128%2C558.25)
Calculate the monthly payment:
Monthly payment = ![\frac{1,128,558.25}{48} =23,511.63](https://tex.z-dn.net/?f=%5Cfrac%7B1%2C128%2C558.25%7D%7B48%7D%20%3D23%2C511.63)
Hence the monthly amortization is P23,511.63
Learn more on compound interest here: brainly.com/question/24924853
Doubling formula is this:
![P(t)=P(2)^{\frac{t}{d}}](https://tex.z-dn.net/?f=P%28t%29%3DP%282%29%5E%7B%5Cfrac%7Bt%7D%7Bd%7D%7D)
where P=initial number of rabbits
t=time
d=time it takes to doulbe
ok, so 4 weeks is the doubling time so that is 4*7=28 days
we wawnt time=98
and oroiginal number of rabbits is 5 so
![P(98)=5(2)^{\frac{98}{28}}](https://tex.z-dn.net/?f=P%2898%29%3D5%282%29%5E%7B%5Cfrac%7B98%7D%7B28%7D%7D)
![P(98)=5(2)^{3.5}](https://tex.z-dn.net/?f=P%2898%29%3D5%282%29%5E%7B3.5%7D)
![P(98)=5(2^3)(\sqrt{2})](https://tex.z-dn.net/?f=P%2898%29%3D5%282%5E3%29%28%5Csqrt%7B2%7D%29)
![P(98)=5(8)\sqrt{2}](https://tex.z-dn.net/?f=P%2898%29%3D5%288%29%5Csqrt%7B2%7D)
![P(98)=40\sqrt{2}](https://tex.z-dn.net/?f=P%2898%29%3D40%5Csqrt%7B2%7D)
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days